Python 如何仅获取特定字符后面的字符串？

如果我有这个密码

import csv
txt_file = r"input.txt"
csv_file = r"Good_data.csv"
in_txt = csv.reader(open(txt_file, "r"), delimiter = ',')
out_csv = csv.writer(open(csv_file, 'w'))
out_csv.writerows(in_txt)

这段代码将字符串从txt移动到excel，但我只希望移动字母Y之后的字符串 例如，这是input.txt中的一行

u'gY': -0.009,Y'gm': 0.0011, Y'ay'

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TQ

您可以使用

正向查找（？您希望以什么格式排列数据？看起来不凌乱，看起来像JSON，不确定它是否格式错误，或者您只是像那样发布它看起来您有字典，您可以使用pandas来获取数据帧…这是文档我很抱歉我没有指定如何排列它…我想通过只打印后面的单词来排列它r字母w字母
Y
？显示了
input.txt
的示例，使我们能够理解您的问题。
import re

pattern = r"(?<=Y)'(\w.+?)'"

string="u'gY': -0.009,Y'gm': 0.0011, Y'ay'"

print(re.findall(pattern,string))

['gm', 'ay']

Positive Lookbehind (?<=Y)
Assert that the Regex below matches
**Y** matches the character Y literally (case sensitive)
**'** matches the character ' literally (case sensitive)
1st Capturing Group **(\w.+?)**
**\w** matches any word character (equal to [a-zA-Z0-9_])
**.+?** matches any character (except for line terminators)
**+?** Quantifier — Matches between one and unlimited times, as few times as possible, expanding as needed (lazy)
' matches the character ' literally (case sensitive)