Python 异步线程超时
简单异步http客户端,在站点不可用的情况下长时间挂起 例如,在网站www.evtur.ru上,它会等待很长时间,十分钟或更长时间 我找不到如何最小化超时的方法,例如,是否可以在5秒内完成超时Python 异步线程超时,python,timeout,asyncore,Python,Timeout,Asyncore,简单异步http客户端,在站点不可用的情况下长时间挂起 例如,在网站www.evtur.ru上,它会等待很长时间,十分钟或更长时间 我找不到如何最小化超时的方法,例如,是否可以在5秒内完成超时 # coding=utf-8 import asyncore import string, socket import StringIO import mimetools, urlparse class AsyncHTTP(asyncore.dispatcher): # HTTP request
# coding=utf-8
import asyncore
import string, socket
import StringIO
import mimetools, urlparse
class AsyncHTTP(asyncore.dispatcher):
# HTTP requestor
def __init__(self, uri):
asyncore.dispatcher.__init__(self)
self.uri = uri
# turn the uri into a valid request
scheme, host, path, params, query, fragment = urlparse.urlparse(uri)
assert scheme == "http", "only supports HTTP requests"
try:
host, port = string.split(host, ":", 1)
port = int(port)
except (TypeError, ValueError):
port = 80 # default port
if not path:
path = "/"
if params:
path = path + ";" + params
if query:
path = path + "?" + query
self.request = "GET %s HTTP/1.0\r\nHost: %s\r\n\r\n" % (path, host)
self.host = host
self.port = port
self.status = None
self.header = None
self.http_code = None
self.data = ""
# get things going!
self.create_socket(socket.AF_INET, socket.SOCK_STREAM)
#self.connect((host, port))
#return
try:
self.connect((host, port))
except Exception,e:
self.close()
self.handle_connect_expt(e)
def handle_connect(self):
self.send(self.request)
def handle_expt(self):
print "handle_expt error!"
self.close()
def handle_error(self):
print "handle_error error!"
self.close()
def handle_connect_expt(self,expt):
print "connection error:",expt
def handle_code(self):
print self.host," : ","recv http code: ",self.http_code
def handle_read(self):
data = self.recv(2048)
#print data
if not self.header:
self.data = self.data + data
try:
i = string.index(self.data, "\r\n\r\n")
except ValueError:
return # continue
else:
# parse header
fp = StringIO.StringIO(self.data[:i+4])
# status line is "HTTP/version status message"
status = fp.readline()
self.status = string.split(status, " ", 2)
self.http_code = self.status[1]
self.handle_code()
# followed by a rfc822-style message header
self.header = mimetools.Message(fp)
# followed by a newline, and the payload (if any)
data = self.data[i+4:]
self.data = ""
#header recived
#self.close()
def handle_close(self):
self.close()
c = AsyncHTTP('http://www.python.org')
c = AsyncHTTP('http://www.evtur.ru')
asyncore.loop(timeout=0.05)
您必须在dispatcher套接字上设置超时。 打完电话
self.create_socket(socket.AF_INET, socket.SOCK_STREAM)
你可以打电话
self.socket.settimeout(nn)
在套接字上设置超时。您还可以像设置任何其他套接字一样设置任何其他套接字选项
self.socket.settimeout(nn)
这似乎对我不起作用
但是,asyncore.loop()的参数名为count。下面是asyncore.loop()的伪代码:
因此,如果您需要5秒钟,您需要执行以下操作:
asyncore.loop(timeout=1, count=5)
但不要建议以这种确切的方式工作。请注意,如果存在“事件”,则可能有5个以上的“计数”。我使用以下代码:
start = int(time.time())
while True:
asyncore.loop(timeout=1, count=5)
print "LOOP : %d enqueued, waiting to finish" % len(asyncore.socket_map)
if len(asyncore.socket_map) == 0 :
break
if int(time.time()) - start > timeout :
print "LOOP : Timeout"
break
我认为你的代码需要一些格式化。你是在混合制表符和空格吗?如果是这样,这是个坏主意。如本主题的其他问题中所述,问题不在于代码,而在于系统设置。可能与否重复,此问题不同(仅代码相同)。这里的问题不在于dns呼叫阻塞。站点访问中的问题(长时间没有服务器响应)和我通过asyncore使用非阻塞套接字搜索最小化超时,是否可能?
start = int(time.time())
while True:
asyncore.loop(timeout=1, count=5)
print "LOOP : %d enqueued, waiting to finish" % len(asyncore.socket_map)
if len(asyncore.socket_map) == 0 :
break
if int(time.time()) - start > timeout :
print "LOOP : Timeout"
break