Python django中基于类别的列表视图
我有两个模型,第一个是类别,第二个是详细信息,我想做一个视图,在那里我可以点击一个类别,链接应该只带我到我点击的当前类别的列表。 我的模型如下:Python django中基于类别的列表视图,python,django,Python,Django,我有两个模型,第一个是类别,第二个是详细信息,我想做一个视图,在那里我可以点击一个类别,链接应该只带我到我点击的当前类别的列表。 我的模型如下: class FoodCategory(models.Model): categoryname = models.CharField(max_length=100) categorydetails = models.CharField(max_length=1000) categoryimage = models.ImageFie
class FoodCategory(models.Model):
categoryname = models.CharField(max_length=100)
categorydetails = models.CharField(max_length=1000)
categoryimage = models.ImageField(default='cat_def.jpg',
upload_to='catimg')
class Meta:
verbose_name = 'Food Category'
def __str__(self):
return self.categoryname
class FoodDetails(models.Model):
fromcategory = models.ForeignKey(FoodCategory,
on_delete=models.CASCADE)
foodname = models.CharField(max_length=100)
fooddetails = models.CharField(max_length=1000)
foodimage = models.ImageField(default='food_def.jpg',
upload_to='fodimg')
armodel = models.CharField(default='andy.sfb', max_length=50)
additiondate = models.DateTimeField(default=timezone.now)
addedby = models.ForeignKey(User, on_delete=models.CASCADE)
class Meta:
verbose_name = 'Food Detail'
def __str__(self):
return self.fromcategory.categoryname + \
' - ' + self.foodname + \
' - ' + 'added by' + \
' - ' + self.addedby.username
def get_absolute_url(self):
return reverse('food-details', kwargs={'pk': self.pk})
views.py文件:
from django.shortcuts import render
from food.models import FoodCategory, FoodDetails
from django.views.generic import ListView, DetailView
class FoodCategoryView(ListView):
model = FoodCategory
template_name = 'food/food-category.html'
context_object_name = 'food'
class FoodListView(ListView):
model = FoodDetails
template_name = 'food/food-list.html'
context_object_name = 'food'
ordering = ['-additiondate']
class FoodDetailsView(DetailView):
model = FoodDetails
template_name = 'food/FoodDetails_detail.html'
还有我的URL.py文件:
from django.urls import path, include
from . import views
from .views import FoodCategoryView, FoodListView, FoodDetailsView
# api url handler
urlpatterns = [
path('category/', FoodCategoryView.as_view(), name='food-
category'),
path('foodlist/', FoodListView.as_view(), name='food-list'),
path('foodlist/<int:pk>/', FoodDetailsView.as_view(),
name='food-details')
]
从django.url导入路径,包括
从…起导入视图
from.views导入FoodCategoryView、FoodListView、FoodDetailsView
#api url处理程序
URL模式=[
路径('category/',FoodCategoryView.as_view(),name='food-
类别),,
路径('foodlist/',FoodListView.as_view(),name='food-list'),
路径('foodlist/',FoodDetailsView.as_view(),
name='food-details')
]
这是我的所有文件,我只想知道获取当前基于类别的食品详细信息的具体方法。您可以通过在列表视图上定义
get\u queryset
来实现这一点
class FoodDetailsByCategory(ListView):
def get_queryset(self):
return FoodDetails.objects.filter(fromcategory_id=self.kwargs['category_id'])
使用简单的URL:
path('category/<int:category_id>', FoodDetailsByCategory.as_view(), name='food_details_by_category')
path('category/',FoodDetailsByCategory.as_view(),name='food_details_by_category')
您可以通过在列表视图上定义get\u queryset
来实现这一点
class FoodDetailsByCategory(ListView):
def get_queryset(self):
return FoodDetails.objects.filter(fromcategory_id=self.kwargs['category_id'])
使用简单的URL:
path('category/<int:category_id>', FoodDetailsByCategory.as_view(), name='food_details_by_category')
path('category/',FoodDetailsByCategory.as_view(),name='food_details_by_category')
我认为您必须阅读Django文档,才能了解如何在Django模板中创建视图并返回结果:这里就是模型。这还不够,欢迎来到SO。请阅读,这样你就知道什么样的问题在这个论坛上是合适的。您需要展示您所面临的特定问题,这不是让其他人为您编写代码的目的。请先写下您的观点,通过阅读文档并亲自尝试来表明您已经做出了努力。当面对一个特定的问题时,你可以在这里询问。我会更新url和视图,我认为你必须阅读Django文档,以了解如何在Django模板中创建视图并返回结果:这里你只有模型。这还不够,欢迎来到SO。请阅读,这样你就知道什么样的问题在这个论坛上是合适的。您需要展示您所面临的特定问题,这不是让其他人为您编写代码的目的。请先写下您的观点,通过阅读文档并亲自尝试来表明您已经做出了努力。当面对一个特定的问题时,你可以在这里询问。我会很快更新url并查看