Python 如何在资源中搜索嵌套值(tastypie json)
您好,我在respurces.py文件中有以下资源Python 如何在资源中搜索嵌套值(tastypie json),python,json,django,tastypie,jsonresponse,Python,Json,Django,Tastypie,Jsonresponse,您好,我在respurces.py文件中有以下资源 class SodResource(ModelResource): class Meta: queryset = Sod.objects.all().order_by('-rank') filtering = {'sod_type': ALL, 'generic_value': ALL} class DeptBpResource(ModelResource): sod_setting = f
class SodResource(ModelResource):
class Meta:
queryset = Sod.objects.all().order_by('-rank')
filtering = {'sod_type': ALL, 'generic_value': ALL}
class DeptBpResource(ModelResource):
sod_setting = fields.ToManyField(SodResource, 'sod', null=True, full=True)
class Meta:
queryset = Dept_Bp.objects.all()
filtering = {
'dept_name': ALL,
'bp_name': ALL,
}
我可以搜索http://10.85.87.116:8000/fmea/api/v1/deptbp/?format=json&dept_name=DEQP&bp_name=Kaizen
。但我的目标是能够搜索sod\u类型
(来自上述资源)。但当我搜索为http://10.85.87.116:8000/fmea/api/v1/deptbp/?format=json&dept_name=DEQP&bp_name=Kaizen&sod_type=1
它只是返回与http://10.85.87.116:8000/fmea/api/v1/deptbp/?format=json&dept_name=DEQP&bp_name=Kaizen
没有缩小我的搜索范围。我对资源或tastypie有点陌生。伙计们,这里怎么了?有什么想法吗?提前谢谢 试试这个:
class SodResource(ModelResource):
class Meta:
queryset = Sod.objects.all().order_by('-rank')
filtering = {'sod_type': ALL, 'generic_value': ALL}
class DeptBpResource(ModelResource):
sod_setting = fields.ToManyField(SodResource, 'sod', null=True, full=True)
class Meta:
queryset = Dept_Bp.objects.all()
filtering = {
'dept_name': ALL,
'bp_name': ALL,
'sod_setting': ALL_WITH_RELATIONS
}
在你的网址上。您可以这样做:
http://10.85.87.116:8000/fmea/api/v1/deptbp/?format=json&dept_name=DEQP&bp_name=Kaizen&sod_setting__type=1