python中具有多个键的字典
我想知道对于每一行[0],相同值在python中具有多个键的字典,python,dictionary,Python,Dictionary,我想知道对于每一行[0],相同值在行[1] 例如: 12245933,1418,1 12245933,1475,2 134514060,6112,3 134514064,10096,4 12245933,1536,5 ... 134514097,16200,38 12245933,1475,39 我试过的代码 12245933 has the value 1475 in line 39 and line 2 .. i want to know all the possible occurre
行[1]
例如:
12245933,1418,1
12245933,1475,2
134514060,6112,3
134514064,10096,4
12245933,1536,5
...
134514097,16200,38
12245933,1475,39
我试过的代码
12245933 has the value 1475 in line 39 and line 2 ..
i want to know all the possible occurrences of 1475 for 12245933 in a file.
也许我们也可以在pc_元素dict中添加第[1]行?从中获取索引 使用
tuple
s作为字典键:
#datafile parser
def parse_data(file):
pc_elements = defaultdict(list)
addr_elements = defaultdict(list)
with open(file, 'rb') as f:
line_number = 0
csvin = csv.reader((x.replace('\0','') for x in f), delimiter = ',')
for row in csvin:
try:
pc_elements[int(row[0])].append(line_number)
addr_elemets[int(row[1])].append(line_number)
line_number += 1
except:
print row
line_number += 1
pass
使用嵌套字典。将1224953映射到字典,该字典将1475映射到值出现的行号列表
所以您的最终字典看起来像{1224953=>{1475=>[39,2]}字典不能有重复的键。除了使用列表,还有其他方法吗?随着大小的增加,列表需要很长时间来处理。我假设第一列是某种类型的
id
,然后您就有了这个id的数据。您可以创建一个以id为键的dict,值将是表示数据的元组列表,即{12245933:[(1418,1),(1475,2)]etcHey您可以连接两个键。我指的是数字:other,并把它放在字典里。exmaple dict[12245933:1475]+=1这不能给出只有一个元组存在的元组吗?@pistal什么?不知道你是什么意思
In [63]: d='''
...: 12245933,1418,1
...: 12245933,1475,2
...: 134514060,6112,3
...: 134514064,10096,4
...: 12245933,1536,5
...: 134514097,16200,38
...: 12245933,1475,39
...: '''
In [64]: from collections import defaultdict
...: dic=defaultdict(list)
...: for l in d.split():
...: tup=tuple(int(i) for i in l.split(','))
...: dic[tup[:2]].append(tup[2])
In [65]: dic[(12245933, 1475)]
Out[65]: [2, 39]