Python 如何从列表中删除从开始到结束的范围enclusive

我有点不知所措，不知道该怎么做。任何帮助都将不胜感激。

简单地说

def remove_section(alist, start, end):
    """
    Return a copy of alist removing the section from start to end inclusive

    >>> inlist = [8,7,6,5,4,3,2,1]
    >>> remove_section(inlist, 2, 5)
    [8, 7, 2, 1]
    >>> inlist == [8,7,6,5,4,3,2,1]
    True
    >>> inlist = ["bob","sue","jim","mary","tony"]
    >>> remove_section(inlist, 0,1)
    ['jim', 'mary', 'tony']
    >>> inlist == ["bob","sue","jim","mary","tony"]
    True
    """

---

应该足够了。

您可以复制列表并删除不需要的部分

del alist[start:end+1]

或者你可以把两片放在一起

newlist = alist[:]
del newlist[start:end]

两种方法的快速计时：

newlist = alist[start:] + atlist[end+1:]

---

第一种方法的速度大约是第二种方法的两倍。

复制序列然后删除片段最简单

print timeit.repeat("b=range(100);a = b[:]; del a[2:8]")
print timeit.repeat("b=range(100);a = b[2:] + b[8:];")

---

这应该满足您的要求：

>>> inlist = [8,7,6,5,4,3,2,1]
>>> outlist = inlist[:]
>>> del outlist[2:6]
>>> outlist
[8, 7, 2, 1]

def remove_section(alist, start, end):
    return alist[:start] + alist[end+1:]