基于python的垃圾模拟器

我正在为这个赌场游戏做一个叫做“垃圾”的程序。我花了很多时间做这件事，但我被卡住了，似乎找不到问题所在。它不能正确地循环，也不能正确地输出

这是到目前为止我的代码

import random
from easygui import *
ans = boolbox("Would you like to play Craps?")
while ans == True:
    d1 = random.randint(1,6)
    d2 = random.randint(1,6)
    point = d1+d2
    counter = 1  
    string = ""
    if point == 7 or point == 11:  
        string += ("Roll #{}: [{}] [{}] ==> WIN!".format(counter,d1,d2))
    elif point == 2 or point == 3 or point == 12:
        string += ("Roll #{}: [{}] [{}] ==> LOSS!".format(counter,d1,d2)) 
    else:
        string += ("Roll #{}: [{}] [{}] ==> 'point' is {}".format(counter, d1,d2,point))
        num = point
        while num != 7:
            if counter == 1:
                string += ("Roll #{}: [{}] [{}] ==> keep going!".format(counter, d1,d2))
                counter +=1
                dice_1 = random.randint(1,6)
                dice_2 = random.randint(1,6)
                num = dice_1 + dice_2
                if num == point:
                    string += ("Roll #{}: [{}] [{}] ==> WIN!".format(counter, dice_1,dice_2))
                    counter +=1
                elif num == 7:
                    string+= ("Roll #{}: [{}] [{}] ==> LOSE!".format(counter, dice_1,dice_2))
                    counter+=1
                else:
                    string+= ("Roll #{}: [{}] [{}] ==> keep going!".format(counter,dice_1,dice_2))

---

以上代码是您尝试执行的操作的简化版本。。它是有效的。特别是，我移动了craps核心函数

import random
from easygui import *

def rollDice(): # simulate a dice roll
    return random.randrange(1,7) + random.randrange(1,7)

def craps(): # roll dice and evaluate results
    firstRoll= rollDice()
    if firstRoll in (7,11):
        return 1 # initial winning condition
    if firstRoll in (2,3,12):
        return 0 #initial losing condition

    while True:
        newRoll = rollDice()
        if newRoll == firstRoll:
            return 1 #secondary winning condition
        if newRoll == 7:
            return 0 #secondary losing condition

ans = boolbox("Would you like to play Craps?")
while ans == True:
    result = craps()
    string = ""
    if( result == 1 ):
        string += ("WIN!")
    else:
        string += ("LOSS!")
    msgbox(string)
    ans = boolbox("Would you like to play Craps?")

编辑：严格赋值？？：）

---

它应该模拟垃圾赌场游戏，你认为问题出在哪里？它现在到底在做什么？请看，我认为问题是在我将num的值更改为point之后，while循环的参数不合适。现在它正在做一堆奇怪的事情，它不应该像无限循环那样在一点上不输出任何东西对不起，但是如果使用while/for循环，如果使用/elif/else，它是否可能呢？哈哈，这不是一个严格的赋值，更像是我们还没有学会这些：P当我运行编辑过的代码时，它会进入一个无限循环？@shahaadn:No，如果你对boolbox问题回答“否”，那么，

ans

变为

False

，while条件变为

False

，因此应用程序退出。如果我的回答帮助你解决了问题，记得接受我的回答。

import random
from easygui import *

ans = boolbox("Would you like to play Craps?")
while ans == True:
    looping = True
    firstRoll = random.randrange(1,7) + random.randrange(1,7)
    if firstRoll in (7,11):
        result = 1 # initial winning condition
        looping = False
    if firstRoll in (2,3,12):
        result = 0 #initial losing condition
        looping = False

    while looping:
        newRoll = random.randrange(1,7) + random.randrange(1,7)
        if newRoll == firstRoll:
            result = 1 #secondary winning condition
            looping = False
        if newRoll == 7:
            result = 0 #secondary losing condition
            looping = False

    string = ""
    if( result == 1 ):
        string += ("WIN!")
    else:
        string += ("LOSS!")
    msgbox(string)
    ans = boolbox("Would you like to play Craps?")