Python 抓取亚马逊评论，不能排除付费评论

我正试图从每一个评论员给一个产品的星星数中剔除。我注意到有些评论员是“藤蔓之声”或付费评论员。他们很少给出4颗星，大部分是5颗星。因此，我想排除它们

我这样做的方式是，如果评论标记为“a-color-success a-text-bold”，则将其标记为“付费”或“未付费”

我似乎无法在vine变量中添加任何“Paid”标记。为什么

只有那些由Vine Voice撰写的评论才有标签，那些没有“付费”标签的评论才没有标签

这就是我目前得到的。 评论2和评论3是Vine Voice，但它们被标记为未付费，但应该付费

0    5.0 out of 5 stars 2019-09-18  Not-paid
1    4.0 out of 5 stars 2019-09-13  Not-paid
2    5.0 out of 5 stars 2019-09-12  Not-paid
3    5.0 out of 5 stars 2019-09-11  Not-paid
4    5.0 out of 5 stars 2019-09-10  Not-paid
...

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将元素与元素进行比较，这就是为什么它总是处于else状态的原因。 我已经做了更改，并将文本与文本进行了比较，它工作正常。请检查下面的代码

import requests
from bs4 import BeautifulSoup
import pandas as pd
import time

headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.3; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/54.0.2840.71 Safari/537.36'}

rating_list = []
date_list = []
vine = []

for num in range(1,12):
    url = "https://www.amazon.com/Jabra-Wireless-Noise-Canceling-Headphones-Built/product-reviews/B07RS8B5HV/ref=cm_cr_arp_d_paging_btm_next_2?ie=UTF8&reviewerType=all_reviews&pageNumber={}&sortBy=recent".format(num)

    r = requests.get(url, headers = headers)

    soup = BeautifulSoup(r.content, 'lxml')

    for ratings in soup.find_all("div", attrs={"data-hook": "review"}):
        submission_date = ratings.find("span", {'data-hook':'review-date'}).text
        rating = ratings.find('i', attrs={"data-hook": "review-star-rating"}).text
        paid = ratings.find("span", attrs={"class": "a-color-success a-text-bold"})
        if paid:

         if paid.text in ratings.text:
             vine.append("Paid")
             date_list.append(submission_date)
             rating_list.append(rating)

             data = {'Rating': rating_list, 'Date': date_list, "Paid": vine}
        else:
            vine.append("Not-paid")

            date_list.append(submission_date)
            rating_list.append(rating)

            data = {'Rating':rating_list, 'Date':date_list, "Paid":vine}
        time.sleep(2)

df = pd.DataFrame(data)
df["Date"] = pd.to_datetime(df["Date"])
df = df.sort_values(by="Date", ascending=False)
print(df)

输出：

          Date      Paid              Rating
0   2019-09-18  Not-paid  5.0 out of 5 stars
1   2019-09-13  Not-paid  4.0 out of 5 stars
2   2019-09-12      Paid  5.0 out of 5 stars
3   2019-09-11      Paid  5.0 out of 5 stars
4   2019-09-10  Not-paid  5.0 out of 5 stars
5   2019-09-10  Not-paid  2.0 out of 5 stars
6   2019-09-10      Paid  5.0 out of 5 stars
7   2019-09-09      Paid  5.0 out of 5 stars
8   2019-09-09  Not-paid  2.0 out of 5 stars
9   2019-09-08      Paid  5.0 out of 5 stars
10  2019-09-05      Paid  5.0 out of 5 stars
11  2019-09-01  Not-paid  2.0 out of 5 stars
12  2019-08-31      Paid  5.0 out of 5 stars
13  2019-08-25      Paid  5.0 out of 5 stars
14  2019-08-24  Not-paid  4.0 out of 5 stars
15  2019-08-22  Not-paid  5.0 out of 5 stars
16  2019-08-21      Paid  5.0 out of 5 stars
17  2019-08-20  Not-paid  5.0 out of 5 stars
18  2019-08-20      Paid  5.0 out of 5 stars
19  2019-08-18      Paid  5.0 out of 5 stars
20  2019-08-17  Not-paid  5.0 out of 5 stars
21  2019-08-17  Not-paid  5.0 out of 5 stars
22  2019-08-14  Not-paid  4.0 out of 5 stars
23  2019-08-12      Paid  5.0 out of 5 stars
24  2019-08-05      Paid  5.0 out of 5 stars
25  2019-08-05      Paid  4.0 out of 5 stars
26  2019-08-04      Paid  5.0 out of 5 stars
27  2019-08-04      Paid  4.0 out of 5 stars
29  2019-08-03      Paid  5.0 out of 5 stars
28  2019-08-03      Paid  4.0 out of 5 stars
..         ...       ...                 ...
80  2019-07-08      Paid  5.0 out of 5 stars
81  2019-07-08      Paid  5.0 out of 5 stars
82  2019-07-08      Paid  5.0 out of 5 stars
85  2019-07-07      Paid  5.0 out of 5 stars
83  2019-07-07      Paid  5.0 out of 5 stars
84  2019-07-07      Paid  5.0 out of 5 stars
87  2019-07-06      Paid  5.0 out of 5 stars
86  2019-07-06      Paid  4.0 out of 5 stars
88  2019-07-05  Not-paid  4.0 out of 5 stars
89  2019-07-05      Paid  5.0 out of 5 stars
90  2019-07-05      Paid  5.0 out of 5 stars
91  2019-07-05      Paid  5.0 out of 5 stars
92  2019-07-04      Paid  5.0 out of 5 stars
93  2019-07-04      Paid  4.0 out of 5 stars
94  2019-07-04      Paid  5.0 out of 5 stars
95  2019-07-04      Paid  5.0 out of 5 stars
96  2019-07-04      Paid  5.0 out of 5 stars
98  2019-07-03  Not-paid  3.0 out of 5 stars
97  2019-07-03      Paid  5.0 out of 5 stars
99  2019-07-01      Paid  5.0 out of 5 stars
100 2019-07-01      Paid  3.0 out of 5 stars
101 2019-07-01      Paid  5.0 out of 5 stars
102 2019-06-30      Paid  5.0 out of 5 stars
103 2019-06-29      Paid  5.0 out of 5 stars
104 2019-06-29      Paid  5.0 out of 5 stars
105 2019-06-28  Not-paid  1.0 out of 5 stars
106 2019-06-27      Paid  4.0 out of 5 stars
107 2019-06-27      Paid  5.0 out of 5 stars
108 2019-06-26      Paid  5.0 out of 5 stars
109 2019-06-26      Paid  5.0 out of 5 stars

[110 rows x 3 columns]

我认为更好的方法（使用bs4.7.1+）是使用：has和：而不是预先进行排除。这样就不需要exclude字段/标志。在下面的示例中，我打印了审阅者姓名作为一个视觉检查（您将看到付费审阅者姓名不会出现）。我还将调整循环以使其正常工作，并使用

会话

提高效率。我还使用更短更健壮的选择器

css选择器比

find

更快，因此我可能会将

find

行更改为：

submission_date = review.select_one('[data-hook=review-date]').text
rating = review.select_one('[data-hook=review-star-rating]').text

---

派克

---

不需要工作。但我也注意到“如果支付”缩进发生了什么？如果元素出现在父标记下，那么检查内部的if item文本val或转到else，这就是如果支付：全部。但是我运行了代码，它给了我未支付和支付选项。奇怪。我不知道为什么我的电脑在窃听。与我自己的代码相比，我只得到了20条评论，都是非付费的。我自己的代码给了我所有110条评论。你添加了输出，它看起来是正确的。我买的是20排的。不知道为什么我们得到如此不同的结果？我做到了。谢谢你的帮助。我想故障出在键盘语言上。所以当我手动输入你的代码时，它工作了！我对这个伪选择器非常敬畏。

：has（）。该脚本能够绕过任何形式的禁令，除了最初出现的验证码。它能够抓取几乎所有的网站，只要内容是静态的，而不是谷歌。总有一天我会把它寄给你的。@SIM我期待着看到它。很高兴看到您使用：has。看起来很有趣。明天将对此进行测试，并将报告！
submission_date = review.select_one('[data-hook=review-date]').text
rating = review.select_one('[data-hook=review-star-rating]').text

import requests
from bs4 import BeautifulSoup
import pandas as pd

headers = {'User-Agent': 'Mozilla/5.0'}
rating_list = [] 
date_list = []

with requests.Session() as s:   
    for num in range(1,12):
        url = "https://www.amazon.com/Jabra-Wireless-Noise-Canceling-Headphones-Built/product-reviews/B07RS8B5HV/ref=cm_cr_arp_d_paging_btm_next_2?ie=UTF8&reviewerType=all_reviews&pageNumber={}&sortBy=recent".format(num)
        r = s.get(url, headers = headers)
        soup = BeautifulSoup(r.content, 'lxml')

        for review in soup.select('.review:not(:has(.a-color-success))'):   
            submission_date = review.select_one('[data-hook=review-date]').text
            rating = review.select_one('[data-hook=review-star-rating]').text
            date_list.append(submission_date)
            rating_list.append(rating)
            print(review.select_one('.a-profile-name').text) #check 
    data = {'Rating':rating_list, 'Date':date_list}

df = pd.DataFrame(data)
df["Date"] = pd.to_datetime(df["Date"])
df = df.sort_values(by="Date", ascending=False)
print(df)