比较python中两个字典列表中的不同键
我试图比较两个字典列表来替换相等的值。例如:比较python中两个字典列表中的不同键,python,Python,我试图比较两个字典列表来替换相等的值。例如: d1 = [{'a': 'hello', 'b':'world','c':'this','d':'is'},{'a':'ddd' ,'b': 'www','c':'hah','d':'tt'},.....] d2 = [{'Q': 'hello', 'H':'target_word','K':'that','N':'was'},{'Q':'world' ,'H': 'target_word','K':'hah','N':'txt'},.....]
d1 = [{'a': 'hello', 'b':'world','c':'this','d':'is'},{'a':'ddd' ,'b': 'www','c':'hah','d':'tt'},.....]
d2 = [{'Q': 'hello', 'H':'target_word','K':'that','N':'was'},{'Q':'world' ,'H': 'target_word','K':'hah','N':'txt'},.....]
有人能告诉我如何将d1中的键('a','b')与d2中的'Q'进行比较吗?如果它们具有相同的值,则必须将d1中的'a'和'b'值替换为d2中的'H'值,即'target\u word'
这是我的一次尝试:
for i in d1:
for j in d2:
for k in i.keys():
for k1 in j.keys():
if j[k1] == i[k]:
i[k] = j ['H']
list.append(i[k])
这个看起来怎么样
d1 = [{'a': 'hello', 'b':'world','c':'this','d':'is'},{'a':'ddd' ,'b': 'www','c':'hah','d':'tt'}]
d2 = [{'Q': 'hello', 'H':'target_word','K':'that','N':'was'},{'Q':'world' ,'H': 'target_word','K':'hah','N':'txt'}]
for input in d1:
for queries in d2:
for val in ("a", "b"):
if input[val] == queries["Q"]:
input[val] = queries["H"]
输出:
>>> d1
[{'a': 'target_word', 'c': 'this', 'b': 'target_word', 'd': 'is'}, {'a': 'ddd', 'c': 'hah', 'b': 'www', 'd': 'tt'}]
您的输出应该是什么?您只需获取公共密钥,并仅对它们进行比较。