检查句型并替换为python中的单词

我试着读一个句子，检查句子中的每个单词是否有撇号，如果有，替换掉，否则继续。我已经在

dict

中定义了撇号。dict的

键

具有模式，

值

具有替换模式的实际值。我尝试了以下代码

tweet = "you're his i'm couldn't can't won't it's"
apostrophes = {"'s":" is","'re":" are","'ll":" will","'d":" would","i'm":"I am","I'm":"I am","won't":"will not", "'ve":" have","can't":"cannot","couldn't":"could not"}

words = tweet.split()

for word in words:
    for k in apostrophes.keys():
       if k in word:
           word = word.replace(k,apostrophes.get(k))
       else:
           pass

---

无需拆分单词并循环：

tweet = "you're his i'm couldn't can't won't it's"
apostrophes = {"'s":" is","'re":" are","'ll":" will","'d":" would","i'm":"I am","I'm":"I am","won't":"will not", "'ve":" have","can't":"cannot","couldn't":"could not"}

for k, v in apostrophes.iteritems():
    tweet = tweet.replace(k, v)

print tweet # you are his I am could not cannot will not it is

---

（请注意，这是python 2.7）

无需拆分单词并循环：

tweet = "you're his i'm couldn't can't won't it's"
apostrophes = {"'s":" is","'re":" are","'ll":" will","'d":" would","i'm":"I am","I'm":"I am","won't":"will not", "'ve":" have","can't":"cannot","couldn't":"could not"}

for k, v in apostrophes.iteritems():
    tweet = tweet.replace(k, v)

print tweet # you are his I am could not cannot will not it is

---

（请注意，这是Python2.7）

除了“它不工作”之外，问题到底是什么？听起来像是试图转义字符串以插入数据库。如果这一点非常接近（不确定为什么还有撇号），那么这种方法是有缺陷的。不要这样做。除了“它不工作”之外，到底是什么问题？听起来好像你在试图转义字符串以插入数据库。如果这一点非常接近（不确定为什么还有撇号），那么这种方法是有缺陷的。不要这样做。如果字典中的值与键（如彼此的子字符串）重叠，这将是一个问题。虽然在原始代码中也会出现同样的问题。它应该适用于这个特定的dict。如果字典中的值与键（如彼此的子字符串）重叠，这将是一个问题。虽然在原始代码中也会出现同样的问题。它应该适用于这个特定的指令。