未定义变量';玩家伤害';-Python文本库游戏

未定义变量';玩家伤害';-Python文本库游戏,python,python-3.x,Python,Python 3.x,这是我在python中的第二个小项目,因为我还在学习,我正在使用参考代码并提出问题来完成这个项目,但我在第49-52行不断收到一个错误“未定义变量‘player_damage’” Sample_FIGHT = { player_damage: "You desperately try to stop the %s for %i damage", enemy_damage: "%s gores you for %i damage", player_win: "The %s collapses wi

这是我在python中的第二个小项目,因为我还在学习,我正在使用参考代码并提出问题来完成这个项目,但我在第49-52行不断收到一个错误“未定义变量‘player_damage’”

Sample_FIGHT = {
player_damage: "You desperately try to stop the %s for %i damage",
enemy_damage: "%s gores you for %i damage",
player_win: "The %s collapses with a thunderous boom",
enemy_win: "You are squished"
}
但我确实在我的函数战斗中定义了变量

def combat (player, enemy):
    player_damage = random.randint (*WEAPONS[player["weapon"]])
    enemy_damage = random.randint(*enemy["attack"])
    player_win = player_damage > enemy["health"]
    enemy_win= enemy_damage  > player["health"]

    return player_damage, player_win , enemy_damage, enemy_win
这就是全部代码

import random

#initial question to start
print ("The Adventures Of Magical Nadia")
Answer = input ("Do you wish to embark on this adventures?")

#Question to start game or end game
if Answer == "Yes" or Answer == "yes":
  print ("You have accepted the adventure. God Speed my young rass!")
else:
  print ("You are a coward and shall not in bark on a great adventure!")

#function for questions avoide repeat 
def ask(question):
    answer = input(question + " [y/n]")
    return answer in ["y", "Y", "Yes", "YES", "yes"]


#Dic of all the weapons in the game
WEAPONS = {
  "Spear": (3, 10), None:(1,3), "knife":(4,16), "Gun":(16,25), "Glass Bottle":(4,16)
}

#Tracking weapon and player health
player = {"weapon":None, "health": (100)}

#to give the player weapons code
player["weapon"] = "Spear"


#Enemys type
enemy = {"name":None, "health":None, "attack":None }
Gaint_spider = {"health":(45), "attack":(7, 10) } 
Dogs = {"health": (50), "attack":(4,15)}
Dragon = {"health": (150), "attack":(35,45)}

#Function each fight gives random dmg, have a player and enemy, winner and loser

def combat (player, enemy):
    player_damage = random.randint (*WEAPONS[player["weapon"]])
    enemy_damage = random.randint(*enemy["attack"])
    player_win = player_damage > enemy["health"]
    enemy_win= enemy_damage  > player["health"]

    return player_damage, player_win , enemy_damage, enemy_win

#Structure of a fight 
Sample_FIGHT = {
player_damage: "You desperately try to stop the %s for %i damage",
enemy_damage: "%s gores you for %i damage",
player_win: "The %s collapses with a thunderous boom",
enemy_win: "You are squished"
}

# describe the fight in a function

def describe_combat(player, enemy, fight_description):
   player_damage, player_win , enemy_damage, enemy_win = combat(player, enemy)

   print (fight_description["player_damage"] % (enemy["name"], player_damage))
   print (fight_description["enemy_damage"] % (enemy["name"], enemy_damage))

   if player_win:
      print (fight_description["player_win"] % enemy["name"])
      return True

   if enemy_win:
      print (fight_description["player_win"] % enemy["name"])
      return False

      return None # fight is a draw

fight_result = describe_combat(player, Gaint_spider, Sample_FIGHT)
if fight_result is None:
   print ("This is a draw")
elif fight_result: 
   print ("You have won the fight")
else:
   print ("You lost")

您在这里定义了一个字典,因此为此您需要传递一个应该是字符串的键变量,如:

Sample_FIGHT = {
"player_damage": "You desperately try to stop the %s for %i damage",
"enemy_damage": "%s gores you for %i damage",
"player_win": "The %s collapses with a thunderous boom",
"enemy_win": "You are squished"
}

您没有任何已定义的关键变量。这就是错误的原因。 因此,只需在下面的代码之前初始化它们

Sample_FIGHT = {
player_damage: "You desperately try to stop the %s for %i damage",
enemy_damage: "%s gores you for %i damage",
player_win: "The %s collapses with a thunderous boom",
enemy_win: "You are squished"
}

所以dict的使用方式,它认为玩家的伤害是一种功能。事实并非如此。这就是为什么会出现错误。您可以像使用字典一样使用字典,但我认为使用类是更好的代码。例如,定义一个玩家类,然后你可以访问像
player.wearm
这样的信息,而不是
player[“wearm”]
@bendl我正计划从头开始重新制作基于文本的游戏,并使用python进入OOP,因为它看起来确实像是更好的代码。谢谢你的提示。