Python 创建panda dataframe并在for循环中附加值
我有一个列表,我想从中迭代并在pandas数据帧中创建元组,以模拟大小为4的滑动窗口。我想做的是:Python 创建panda dataframe并在for循环中附加值,python,list,dataframe,append,Python,List,Dataframe,Append,我有一个列表,我想从中迭代并在pandas数据帧中创建元组,以模拟大小为4的滑动窗口。我想做的是: tuples = pd.DataFrame() for index, row in expertsDF.iterrows(): newlst = row['name'] counter = 0 for x in newlst: if counter < len(newlst) - 3: tuples['A'] =
tuples = pd.DataFrame()
for index, row in expertsDF.iterrows():
newlst = row['name']
counter = 0
for x in newlst:
if counter < len(newlst) - 3:
tuples['A'] = x
tuples['B'] =newlst(counter+1)
tuples['C'] =newlst(counter+2)
tuples['D'] =newlst(counter+3)
counter = counter + 1
我的数据框应该是这样的:
list (var1, var2, var3....)
A B C D
1 var1 var2 var3 var4
2 var2 var3 var4 var5
3 var3 var4 var5 var6
在python中有这样做的方法吗?很接近吗
import pandas as pd
tuples = pd.DataFrame(columns=['A', 'B', 'C', 'D'])
newlst = "abcdefg"
i = 0
for x in newlst:
if i < len(newlst) - 3:
t = pd.DataFrame([[x, newlst[i + 1], newlst[i + 2], newlst[i + 3]]],
columns=['A', 'B', 'C', 'D'])
tuples = tuples.append(t, ignore_index=True)
i += 1
print tuples
如何从系列对象创建数据帧
import pandas as pd
data_list = list(map(lambda x: 'var{}'.format(x),range(0,100)))
df = pd.Series(data_list[0:97]).to_frame(name='A')
df['B'] = pd.Series(data_list[1:98])
df['C'] = pd.Series(data_list[2:99])
df['D'] = pd.Series(data_list[3:100])
df.head()
# output
# A B C D
# 0 var0 var1 var2 var3
# 1 var1 var2 var3 var4
# 2 var2 var3 var4 var5
# 3 var3 var4 var5 var6
# 4 var4 var5 var6 var7
你可以发布一个输出的示例吗?if条件中的代码不正确,因此我没有输出。我只是想展示一下我在做什么。好了,@345243lkj完成了!对不起,什么是
expertsDF.iterrows()
?它来自库itertools。我使用它来迭代存储我的值的初始数据帧。
import pandas as pd
data_list = list(map(lambda x: 'var{}'.format(x),range(0,100)))
df = pd.Series(data_list[0:97]).to_frame(name='A')
df['B'] = pd.Series(data_list[1:98])
df['C'] = pd.Series(data_list[2:99])
df['D'] = pd.Series(data_list[3:100])
df.head()
# output
# A B C D
# 0 var0 var1 var2 var3
# 1 var1 var2 var3 var4
# 2 var2 var3 var4 var5
# 3 var3 var4 var5 var6
# 4 var4 var5 var6 var7