Python 在pandas中的某些字符之前选择部分字符串名称

我有很多列名称，格式如下：

A-1_45_GG___________________LL
B_2_45_GLKK___________________KK

---

我正在寻找一种在长下划线字符之前选择字符串名称的通用方法。因此，我想要的输出将被重命名为

[A-1_45_GG，B_2_45_GL]

。在Python中如何实现这一点？

如果您的名字中没有双下划线，您可以将其拆分为“\uuuuuuu”，然后使用第一个索引

string = "A-1_45_GG___________________LL"
string.split("__")[0]

输出：

'A-1_45_GG'

yourlist = ["A-1_45_GG___________________LL", "B_2_45_GLKK___________________KK"]

print(list(map(lambda x: x.split("__")[0], yourlist)))

['A-1_45_GG', 'B_2_45_GLKK']

['A-1_45_GG', 'B_2_45_GLKK']

如果要使用列表：

'A-1_45_GG'

yourlist = ["A-1_45_GG___________________LL", "B_2_45_GLKK___________________KK"]

print(list(map(lambda x: x.split("__")[0], yourlist)))

['A-1_45_GG', 'B_2_45_GLKK']

['A-1_45_GG', 'B_2_45_GLKK']

输出：

'A-1_45_GG'

yourlist = ["A-1_45_GG___________________LL", "B_2_45_GLKK___________________KK"]

print(list(map(lambda x: x.split("__")[0], yourlist)))

['A-1_45_GG', 'B_2_45_GLKK']

['A-1_45_GG', 'B_2_45_GLKK']

---

如果你的名字中没有双下划线，你可以把它除以“\uuuuuuuuuuuuuuuuuu”，然后取第一个索引

string = "A-1_45_GG___________________LL"
string.split("__")[0]

输出：

'A-1_45_GG'

yourlist = ["A-1_45_GG___________________LL", "B_2_45_GLKK___________________KK"]

print(list(map(lambda x: x.split("__")[0], yourlist)))

['A-1_45_GG', 'B_2_45_GLKK']

['A-1_45_GG', 'B_2_45_GLKK']

如果要使用列表：

'A-1_45_GG'

yourlist = ["A-1_45_GG___________________LL", "B_2_45_GLKK___________________KK"]

print(list(map(lambda x: x.split("__")[0], yourlist)))

['A-1_45_GG', 'B_2_45_GLKK']

['A-1_45_GG', 'B_2_45_GLKK']

输出：

'A-1_45_GG'

yourlist = ["A-1_45_GG___________________LL", "B_2_45_GLKK___________________KK"]

print(list(map(lambda x: x.split("__")[0], yourlist)))

['A-1_45_GG', 'B_2_45_GLKK']

['A-1_45_GG', 'B_2_45_GLKK']

---

另一种方法是通过正则表达式拆分字符串

import re

lst = ["A-1_45_GG___________________LL", "B_2_45_GLKK___________________KK"]

print([re.split("[_]{2,}", i)[0] for i in lst])

输出：

---

另一种方法是通过正则表达式拆分字符串

import re

lst = ["A-1_45_GG___________________LL", "B_2_45_GLKK___________________KK"]

print([re.split("[_]{2,}", i)[0] for i in lst])

输出：