Python 为一个表创建多个外键时发生SqlAlchemy错误

我是新使用sqlAlchemy的人，在创建新表时遇到问题，特别是当出现指向1个表的2个外键时：

class Offers(db.Model):
    __tablename__ = 'offers'
    id = db.Column(db.Integer, primary_key=True, autoincrement=True)
    contact_ign = db.Column(db.String(100))
    conversion_rate = db.Column(db.Float)
    stock = db.Column(db.Integer)
    create_date = db.Column(db.DateTime(timezone=True), default=func.now())
    currency_pair = db.relationship('CurrencyPairs', backref='pair', lazy='dynamic')

class CurrencyPairs(db.Model):
    __tablename__ = 'currency_pairs'
    id = db.Column(db.Integer, primary_key=True, autoincrement=True)
    league = db.Column(db.String(100))
    pair_id = db.Column(db.Integer, db.ForeignKey('offers.id'))
    want = db.relationship('Currency', backref='want', lazy='dynamic')
    have = db.relationship('Currency', backref='have', lazy='dynamic')

class Currency(db.Model):
    __tablename__ = 'currency'
    id = db.Column(db.Integer, primary_key=True, autoincrement=True)
    name = db.Column(db.String(100), nullable=False)
    poe_trade = db.Column(db.Integer, nullable=False)
    poe_official = db.Column(db.String(10), nullable=False)
    tier = db.Column(db.Integer, nullable=False)
    want_id = db.Column(db.Integer, db.ForeignKey('currency_pairs.id'))
    have_id = db.Column(db.Integer, db.ForeignKey('currency_pairs.id'))

我得到的错误是：

sqlalchemy.exc.InvalidRequestError: One or more mappers failed to initialize - can't proceed with initialization of other mappers. Triggering mapper: 'Mapper|CurrencyPairs|currency_pairs'. Original exception was: Could not determine join condition b
etween parent/child tables on relationship CurrencyPairs.want - there are multiple foreign key paths linking the tables.  Specify the 'foreign_keys' argument, providing a list of those columns which should be counted as containing a foreign key refe
rence to the parent table

我尝试了不同的事情，但得到了相同的结果。 我做错了什么？

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提前谢谢。

我知道这是一个老问题，但我也有同样的问题。我希望能帮助别人找到答案

sqlalchemy文档中讨论了这个问题

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按照您编写代码的方式，sqlalchemy无法真正理解选择哪种关系，因为您有两个相同的关系。因此，您必须向sqlalchemy描述同一个表有两个关系。

我知道这是一个老问题，但我也有同样的问题。我希望能帮助别人找到答案

sqlalchemy文档中讨论了这个问题

---

按照您编写代码的方式，sqlalchemy无法真正理解选择哪种关系，因为您有两个相同的关系。因此，您必须向sqlalchemy说明，同一个表有两个关系。

在看到post@SuperShoot的示例后，该计算可能重复，谢谢mate在看到post@SuperShoot的示例后，该计算可能重复，谢谢mate

class Offers(db.Model):
    __tablename__ = 'offers'
    id = db.Column(db.Integer, primary_key=True, autoincrement=True)
    contact_ign = db.Column(db.String(100))
    conversion_rate = db.Column(db.Float)
    stock = db.Column(db.Integer)
    create_date = db.Column(db.DateTime(timezone=True), default=func.now())
    currency_pair = db.relationship('CurrencyPairs', backref='pair', lazy='dynamic')

class CurrencyPairs(db.Model):
    __tablename__ = 'currency_pairs'
    id = db.Column(db.Integer, primary_key=True, autoincrement=True)
    league = db.Column(db.String(100))
    pair_id = db.Column(db.Integer, db.ForeignKey('offers.id'))

    want_currency = relationship("Currency", foreign_keys='[Currency.want_id]', back_populates="want_currency_pairs")
    have_currency = relationship("Currency", foreign_keys='[Currency.have_id]', back_populates="have_currency_pairs")

class Currency(db.Model):
    __tablename__ = 'currency'
    id = db.Column(db.Integer, primary_key=True, autoincrement=True)
    name = db.Column(db.String(100), nullable=False)
    poe_trade = db.Column(db.Integer, nullable=False)
    poe_official = db.Column(db.String(10), nullable=False)
    tier = db.Column(db.Integer, nullable=False)

    want_currency_pairs = relationship(CurrencyPairs, foreign_keys="[Currency.want_id]", back_populates="want_currency")
    have_currency_pairs = relationship(CurrencyPairs, foreign_keys="[Currency.have_id]", back_populates="have_currency")