Python 为什么从文件中导入函数会给出;未解析的引用[文件名]“;?
我在同一个目录下的Intellij中有两个文件:Python 为什么从文件中导入函数会给出;未解析的引用[文件名]“;?,python,intellij-idea,python-import,Python,Intellij Idea,Python Import,我在同一个目录下的Intellij中有两个文件:\uuuu init\uuuuuuuuuuuuuuuuuuuuuuupy和\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu \uuuu init\uuuuu.py设置为我的“运行配置”中的脚本,因此当我按下运行按钮时,它将运行 我在\uuuu init\uuuuu.py中导入的代码如下: from __resources__ import func_test func_test() 但是,中的给出了一个错误:未
\uuuu init\uuuuuuuuuuuuuuuuuuuuuuupy
和\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
\uuuu init\uuuuu.py
设置为我的“运行配置”中的脚本,因此当我按下运行按钮时,它将运行
我在\uuuu init\uuuuu.py
中导入的代码如下:
from __resources__ import func_test
func_test()
但是,
中的给出了一个错误:未解析的引用“\uuuuuuuu资源”
这是我的项目的文件结构:
我认为它可能与PYTHONPATH
或PATH
环境变量有关,但我不确定要更改什么。我将目录添加到两个路径中。您不应该将主应用程序代码放在\uuu init\uuuu.py
中。使用\uuuu main\uuuuuuuuuuuuuuuuuuuuuuupy
(如果您想直接调用包,例如在zip文件中),或者只使用以您的项目命名的模块(例如foo.py
)。您还应该知道,任何以两个下划线开头和结尾的符号都是Python保留的——您应该避免在该模式中使用任何名称,除非您打算使用该语言的一个文档化功能。“您还应该知道,任何以两个下划线开头和结尾的符号都是Python保留的——您应该避免在该模式中使用任何名称,除非您打算使用该语言的文档化功能。”-Daniel Pryden
基本上,将\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuStatement.在Python 2.7.13和3.6.1中对我都很好。我创建了模块并将其保存在名为\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu用于将它们所在的目录放入包中,当您尝试使用两个文件所在的目录名导入包中的模块时,会隐式执行。这是我在Intellij中运行的主类。@martineauinit.py是在我创建源文件夹时自动生成的,所以这不应该是问题,对吗?我将resources.py文件夹重命名为resources.py,但它没有解决问题。不过,感谢您的命名建议。在修复之后,无效并重新启动修复了我的问题。谢谢!请确保文件名周围没有uuuuu。