如何在python中加密用户输入？

我试图用python编写一段代码，对用户输入进行加密。 例如，如果我写“name”，输出应该是“obnf”。但问题是，现在的输出仅为“o”，因此只有第一个字母通过循环，其余字母被忽略。 有什么建议吗？ 这是我的密码

userInput = input("write something: ")


letters = iter(["A","B","C","D", "E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","X","Y","Z","0","1","2","3","4","5","6","7","8","9","a","b","c", "d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"])


def Encoding(user_input):
    encrypted_msg = ""
    for i in range(len(user_input)):
        char = user_input[i]
        if char in letters:
            encrypted_msg += next(letters)
    return encrypted_msg

print(Encoding(userInput))

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一个interator只能被遍历一次，然后它就耗尽了。改用

列表

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考虑并快速替换。

下面的代码解决了问题：

从cryptography.fernet导入fernet
def编码（用户输入，键）：
返回Fernet（key）.encrypt（字节（bytearray（用户输入，编码='UTF-8'））
def解码（加密_输入，密钥）：
返回Fernet（密钥）。解密（加密输入）。解码（“UTF-8”）
如果uuuu name uuuuuu='\uuuuuuu main\uuuuuuu'：
userInput=input（“写东西：”）
key=Fernet.generate_key（）
encryptedInput=编码（用户输入，密钥）
打印（加密输出）
decryptedInput=解码（encryptedInput，密钥）
打印（解密输入）

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干杯

这是一个凯撒密码，移位为1。这份复制件有19个答案，你可以从中选择，这些答案将揭示你到底做错了什么。顺便说一句，你的代码并不完全正确。而不是在迭代中使用<代码> NeX/CODE，考虑转换为列表并查找字母数组中字符所在的索引，然后递增1以访问最终字符。