TypeError:/：'；str'；和'；int'；用python

我正在做一个项目，寻找学生三次考试的平均成绩

我的工作似乎一切正常，但我收到的一个错误是以下几行：

student_avg = ((firstterm) +str (midterm) +str (final)) / 3 

该程序是讲师的配套应用程序。我的教授让我做第一学期的期中考试和期末考试，共5门课

工作了一周后，我在这方面仍然面临一些问题。 有人能检查一下我的代码，看看我的错误是什么吗

def determine_score(grade):
    if 95<= grade <=100:
        return 'A+'
    elif 91<= grade <=96:
        return 'A'
    elif 89<= grade <=92:
        return 'A-'
    elif 85<= grade <=90:
        return 'B+'
    elif 81<= grade <=86:
        return 'B'
    elif 79<= grade <=82:
        return 'B-'
    elif 75<= grade <=80:
        return 'C+'
    elif 72<= grade <=76:
        return 'C'
    elif 64<= grade <=73:
        return 'D'
    elif 0<= grade <=65:
        return 'F'
    else:
        return 'invalide score'

def firstTerm():
    fst_sub1=int(input("Enter first term marks of the first subject: "))
    fst_sub2=int(input("Enter first term marks of the second subject: "))
    fst_sub3=int(input("Enter first term marks of the third subject: "))
    fst_sub4=int(input("Enter first term marks of the fourth subject: "))
    fst_sub5=int(input("Enter first term marks of the fifth subject: "))
    firsttermScore = (fst_sub1+fst_sub2+fst_sub3+fst_sub4+fst_sub5)/5
    return 'firsttermScore'

def midTerm():
    mid_sub1=int(input("Enter mid term marks of the first subject: "))
    mid_sub2=int(input("Enter mid term marks of the second subject: "))
    mid_sub3=int(input("Enter mid term marks of the third subject: "))
    mid_sub4=int(input("Enter mid term marks of the fourth subject: "))
    mid_sub5=int(input("Enter mid term marks of the fifth subject: "))
    midtermScore = (mid_sub1+mid_sub2+mid_sub3+mid_sub4+mid_sub5)/5
    return 'midtermScore'

def final():
    fnl_sub1=int(input("Enter final marks of the first subject: "))
    fnl_sub2=int(input("Enter final marks of the second subject: "))
    fnl_sub3=int(input("Enter final marks of the third subject: "))
    fnl_sub4=int(input("Enter final marks of the fourth subject: "))
    fnl_sub5=int(input("Enter final marks of the fifth subject: "))
    finalScore = (fnl_sub1+fnl_sub2+fnl_sub3+fnl_sub4+fnl_sub5)/5
    return 'finalScore'

total = 0
highest = 0
numStudents = int (input("How Many Students are there? "))
while numStudents < 0 or numStudents > 100:
    numStudents = int (input("Please enter a number between 0 and 100? "))

for i in range (numStudents):
    student_name = (input("Enter Student's Name Please: "))
    firstterm = firstTerm()
    midterm = midTerm()
    final = final()
    student_avg = ((firstterm) +str (midterm) +str (final)) / 3 
    if (highest < student_avg):
        highest = student_avg
        grade = student_avg  
        winner = student_name
        list_marks = []
        list_marks.append([student_name, student_avg,])
        print ("exam result: ", list_marks, "grade is: ", determine_score(grade))


print ("The Student with the higgest average is: ", winner, "With the highest average of: ", highest, "gpa is: " + determine_score(grade) )

def确定分数（等级）：
如果在最终打印语句中，您需要确保所有内容都是字符串：

print ("The Student with the higgest average is: ", winner, "With the highest average of: ", str(highest), "gpa is: " + determine_score(grade) )

print ("exam result: ", str(list_marks), "grade is: ", determine_score(grade))

此外，函数应返回值，而不是硬编码字符串：

return firsttermScore
...
return midtermScore
...
return finalScore

如果您想获得准确的分数，还需要对双精度（或浮动）进行操作：

firsttermScore = (fst_sub1+fst_sub2+fst_sub3+fst_sub4+fst_sub5)/5.0

finalScore = (fnl_sub1+fnl_sub2+fnl_sub3+fnl_sub4+fnl_sub5)/5.0

midtermScore = (mid_sub1+mid_sub2+mid_sub3+mid_sub4+mid_sub5)/5.0

student_avg = (firstterm + midterm + final) / 3.0

如果除以整数，则输入数据为整数。结果将为整数，您将失去精度

最后一个print语句将失败，因为list_标记是一个列表而不是字符串：

print ("The Student with the higgest average is: ", winner, "With the highest average of: ", str(highest), "gpa is: " + determine_score(grade) )

print ("exam result: ", str(list_marks), "grade is: ", determine_score(grade))

还有最后一个错误：

finalGrade = final()

您需要将变量的名称更改为与函数不同的名称。
您的函数执行一些操作（包括一些计算），然后返回字符串。然后调用它们并将字符串除以3。那是不对的。请用代码解释一下好吗？我的问题只有student_avg几乎要花3小时来解决它，但我不能，例如，在final（）中，返回字符串“finalScore”，而不是变量finalScore。第一学期和期中也是如此。更改这些函数以返回变量并再次检查。在
firstTerm
中，将
return'firsttermScore'
替换为
return firsttermScore
（丢失引号），与
中期
和
最终
相同。然后在
student\u avg=（（第一学期）+str（期中）+str（期末））/3
中丢失
str
s.any1请告诉我如何列出所有的学生成绩谢谢你的帮助。student\u avg呢？在student\u avg中，你是在强迫事情成为字符串并使用“+”符号。字符串由“+”号连接，因此您告诉解释器计算“firsttermScoremidtermScorefinalScore”/3，这不是您想要做的。您的第一条语句（
print
）是错误的。它应该像问题中那样工作，我已经修好了。在问题中，“highest”是一个数字，而不是字符串。那也会崩溃的。尽管如此，我还是添加了一个不必要的字符串转换。现在第62行final=final（）float对象上的问题不可调用