Python中的Sleep函数不允许更新以前的信息

嘿，我只是做了一个基本的登录程序，同时了解tkinter，但我遇到了一个问题。如果您运行以下代码，当您点击“登录”时，状态标签不会更新为绿色且“有效”，而登录按钮只是保持按下5秒钟，然后窗口就会被破坏

import tkinter  # import tkinter module
from time import sleep  # import sleep

# define global variables for functions to access
window, main_window, text_status, status, ent, ent2, ent3 = None, None, None, None, None, None, None


def get_input():
    global window, text_status, status, ent, ent2, ent3

    username = ent.get()

    password = ent2.get()

    verified_password = ent3.get()

    num_digits = 0

    for char in password:
        if char.isdigit():
            num_digits += 1

    # loop repeats while:
    # there are less than 2 numbers in the password
    # the passwords length is less than 6 or greater than 10
    if password == verified_password and num_digits >= 2 and 10 >= len(password) >= 6:
        status["fg"] = "green"
        text_status.set("Valid (%s, %s)" % (username, password))

        # open userfile and save userinfo
        with open("userfile.txt","a") as userfile:
            userfile.write(username + " " + password + " " + verified_password + " ")

        sleep(5)
        window.destroy()

    elif password != verified_password:
        status["fg"] = "red"
        text_status.set("Passwords don't match")

    else:
        status["fg"] = "red"
        text_status.set("Not Valid")
        print("Pass must be between 6 - 10 (inclusive) chars and contain 2 numbers. Note Password is case sensitive")

def new_user():

    global window, main_window, text_status, status, ent, ent2, ent3

    # close startup window
    main_window.destroy()

    window = tkinter.Tk()  # create a new window
    window.title("Login Screen")  # specifies window title
    #window.wm_iconbitmap('icon.ico')  # changes icon
    window.geometry("200x170")  # specifies window size

    #Username and password status label
    text_status = tkinter.StringVar()
    text_status.set("Not Valid")
    status = tkinter.Label(window, textvariable=text_status, fg="red")


    un_lbl = tkinter.Label(window, text="Username:")  # create new label
    ent = tkinter.Entry(window)  # create a text entry widget
    ps_lbl = tkinter.Label(window, text="Password:")
    ent2 = tkinter.Entry(window)
    v_ps_lbl = tkinter.Label(window, text="Verify Password:")
    ent3 = tkinter.Entry(window)
    btn = tkinter.Button(window, text="Login", command=get_input)  # create a button

    # pack (add) widgets into window
    status.pack()
    un_lbl.pack()
    ent.pack()
    ps_lbl.pack()
    ent2.pack()
    v_ps_lbl.pack()
    ent3.pack()
    btn.pack()

    window.mainloop()  # draw the window and start application


def login():
    return


def startup():

    global main_window

    main_window = tkinter.Tk()
    main_window.title("Welcome")
    # main_window.geometry("500x100")

    greeting = tkinter.Label(main_window, text="Hello please choose one of the following")
    login_button = tkinter.Button(main_window, text="Login", command=login)
    mk_acc_button = tkinter.Button(main_window, text="Make Account", command=new_user)

    #greeting.pack()
    #login_button.pack()
    #mk_acc_button.pack()

    greeting.grid(column=0, row=0, columnspan=2)
    login_button.grid(column=0, row=1)
    mk_acc_button.grid(column=1, row=1)

    main_window.mainloop()

startup()

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mainloop

没有线程化。这意味着任何sleep和其他deley都会影响循环的运行

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我建议您使用某种异步计时器。

这对我没有帮助，伙计。在窗口被释放之前需要等待一段时间。过一段时间后不要运行程序。user.after（）那么你的问题就不够清楚了。