Python 收件人列表为';t在django中获取电子邮件地址
我在django中发送smtp电子邮件时遇到问题。我尝试使用User model=>get\u email=User.objects.filter(is\u admin=True.values\u list('email')获取电子邮件地址 但是当我将它传递给收件人列表时,它找不到电子邮件地址。以下是我的视图.py:Python 收件人列表为';t在django中获取电子邮件地址,python,django,smtp,sendmail,mail-server,Python,Django,Smtp,Sendmail,Mail Server,我在django中发送smtp电子邮件时遇到问题。我尝试使用User model=>get\u email=User.objects.filter(is\u admin=True.values\u list('email')获取电子邮件地址 但是当我将它传递给收件人列表时,它找不到电子邮件地址。以下是我的视图.py: from django.shortcuts import render from feedbacks.models import Feedback from django.cont
from django.shortcuts import render
from feedbacks.models import Feedback
from django.contrib import messages
from django.core.mail import send_mail
from django.conf import settings
from django.contrib.auth import get_user_model
User = get_user_model()
def feedback(request):
status = Feedback.objects.all()
get_email = User.objects.filter(is_admin=True).values_list('email')
print(get_email)
if request.method == 'POST':
name = request.POST["name"]
student_id = request.POST["student_id"]
adviser_init = request.POST["adviser_init"]
phone = request.POST["phone"]
email = request.POST["email"]
issues = request.POST["issues"]
obj = Feedback.objects.create(name=name, student_id=student_id,
adviser_init=adviser_init, phone=phone,
email=email, issues=issues)
obj.save()
try:
subject = 'Student Feedback'
message = "Mail from Student ID:" + student_id + "\nIssue:" + issues + ""
email_from = settings.EMAIL_HOST_USER
send_mail(subject, message, email_from, [get_email])
messages.success(request, 'Your issue has been sent to our admin. '
'Check feedback status for update. Thank You!')
except:
messages.error(request, 'Feedback Saved but not send to admin.')
context = {
'status': status
}
return render(request, 'feedback/feedback.html', context)
收件人列表必须是
列表
对象,而不是我认为的Queryset或任何其他类似数组的对象。因此,将以下修改添加到get\u mail
变量中:
mail\u qs=User.objects.filter(is\u admin=True).values\u list('email',flat=True)
获取邮件=列表(邮件)
如果queryset不是空的,则应该工作