Python 循环字典值
我目前有一个程序,它读取一个文本文件,并根据里面的输入回答一组查询。这有助于查明被询问儿童的母亲是谁。我现在更进一步,重新处理提供的这些输出,以显示完整的族谱 这是一个文本文件,左侧包含父母,右侧包含孩子。下面是询问的问题,然后是输出Python 循环字典值,python,dictionary,python-3.x,Python,Dictionary,Python 3.x,我目前有一个程序,它读取一个文本文件,并根据里面的输入回答一组查询。这有助于查明被询问儿童的母亲是谁。我现在更进一步,重新处理提供的这些输出,以显示完整的族谱 这是一个文本文件,左侧包含父母,右侧包含孩子。下面是询问的问题,然后是输出 Sue: Chad, Brenda, Harris Charlotte: Tim Brenda: Freddy, Alice Alice: John, Dick, Harry mother Sue ancestors Harry ancestors Bernar
Sue: Chad, Brenda, Harris
Charlotte: Tim
Brenda: Freddy, Alice
Alice: John, Dick, Harry
mother Sue
ancestors Harry
ancestors Bernard
ancestors Charlotte
>>> Mother not known
>>> Alice, Brenda, Sue
>>> Unknown Person
>>> No known ancestors
这个程序能够计算出母亲是谁(感谢Kampu的帮助),但我现在正试图理解如何获取这个值,并可能将其附加到一个新的列表或字典中,在那里无限循环以查找任何可能的祖父母
def lookup_ancestor(child):
ancestor = REVERSE_MAP.get(child)
if ancestor:
ANCESTOR_LIST_ADD.append(ancestor)
if ancestor not in LINES[0:]:
print("Unknown person")
else:
print("No known ancestors")
这就是我到目前为止所做的,REVERSE\u MAP
将每个孩子映射到字典中的父母。然后,我将这些父母放入一个新的列表中,我计划再次运行该列表,以确定他们的父母是谁。然而,我被困在这一点上,因为我找不到一种优雅的方式来执行整个过程,而不创建三个新列表来继续循环。目前的设置方式是,我假设我需要通过for
循环附加它们,或者只是split()
之后的值,以使所有值彼此保持一致。理想情况下,我想学习如何循环这个过程,并找出每个问题的祖先是谁
我觉得自己似乎已经掌握了它的可能外观,但我对Python的了解使我的尝试和错误方法无法达到时间效率
任何帮助都将不胜感激
编辑:链接-
编辑2:
def process_commands(commands, relation_dict):
'''Processes the output'''
output = []
for c in commands:
coms = c.split()
if len(coms) < 2:
output.append("Invalid Command")
continue
action = coms[0]
param = coms[1]
def mother_lookup(action, param, relation_dict):
output_a = []
if action == "mother":
name_found = search_name(relation_dict, param)
if not name_found:
output_a.append("Unknown person")
else:
person = find_parent(relation_dict, param)
if person is None:
output_a.append("Mother not known")
else:
output_a.append(person)
return output_a
def ancestor_lookup(action, param, relation_dict):
output_b = []
if action == "ancestors":
name_found = search_name(relation_dict, param)
if not name_found:
output_b.append("Unknown person")
else:
ancestor_list = []
person = param
while True:
person = find_parent(relation_dict, person)
if person == None:
break
else:
ancestor_list.append(person)
if ancestor_list:
output_b.append(", ".join(ancestor_list))
else:
output_b.append("No known ancestors")
return output_b
def main():
'''Definining the file and outputting it'''
file_name = 'relationships.txt'
relations,commands = read_file(file_name)
#Process Relqations to form a dictionary of the type
#{parent: [child1,child2,...]}
relation_dict = form_relation_dict(relations)
#Now process commands in the file
action = process_commands(commands, relation_dict)
param = process_commands(commands, relation_dict)
output_b = ancestor_lookup(action, param, relation_dict)
output_a = mother_lookup(action, param, relation_dict)
print('\n'.join(output_a))
print ('\n'.join(output_b))
if __name__ == '__main__':
main()
def进程命令(命令、关系命令):
''处理输出''
输出=[]
对于命令中的c:
coms=c.split()
如果len(coms)<2:
append(“无效命令”)
持续
动作=通信量[0]
参数=coms[1]
定义母亲查找(操作、参数、关系):
输出_a=[]
如果操作==“母亲”:
name\u found=搜索名称(关系dict,参数)
如果未找到名称,\u:
输出附加(“未知人员”)
其他:
person=查找父项(关系dict,参数)
如果此人没有:
输出附加(“母亲不知道”)
其他:
输出追加(人)
返回输出_a
定义祖先查找(操作、参数、关系):
输出_b=[]
如果操作==“祖先”:
name\u found=搜索名称(关系dict,参数)
如果未找到名称,\u:
输出附加(“未知人员”)
其他:
祖先列表=[]
person=param
尽管如此:
person=查找父对象(关系,个人)
如果person==无:
打破
其他:
祖先列表。附加(个人)
如果您需要列表:
输出附加(“,”.join(祖先列表))
其他:
输出附加(“无已知祖先”)
返回输出
def main():
''定义文件并输出''
文件名='relationships.txt'
关系,命令=读取文件(文件名)
#处理关系以形成类型的字典
#{家长:[child1,child2,…]}
关系dict=形式关系dict(关系)
#现在处理文件中的命令
动作=处理命令(命令、关系命令)
param=过程命令(命令、关系命令)
输出=祖先查找(操作、参数、关系)
输出=母亲查找(操作、参数、关系)
打印('\n'.join(输出_a))
打印('\n'.连接(输出_b))
如果uuuu name uuuuuu='\uuuuuuu main\uuuuuuu':
main()
您使用祖先列表添加的方式表明,它的定义如下:
global ANCESTOR_LIST_ADD
ANCESTOR_LIST_ADD = []
如果是这种情况,并且祖先\u LIST\u ADD是全局的,您可以调用递归,它将填充祖先,直到出现以下情况:
def lookup_ancestor(child):
ancestor = REVERSE_MAP.get(child)
if ancestor:
ANCESTOR_LIST_ADD.append(ancestor)
lookup_ancestor(ancestor) #recursion
if ancestor not in LINES:
print("Unknown person")
else:
print("No known ancestors")
如果祖先列表添加是局部变量,则需要将其作为调用的一部分传递:
def lookup_ancestor(child, ANCESTOR_LIST_ADD):
ancestor = REVERSE_MAP.get(child)
if ancestor:
ANCESTOR_LIST_ADD.append(ancestor)
return lookup_ancestor(ancestor, ANCESTOR_LIST_ADD) #recursion
if ancestor not in LINES:
print("Unknown person")
else:
print("No known ancestors")
return ANCESTOR_LIST_ADD
我还没有测试过它,但一般的想法是使用递归。正如@NullUserException所说,树(或类似的东西)是一个不错的选择。 我发布的答案与您为这个问题选择的答案完全不同 可以定义一个Person对象,该对象知道其名称并跟踪其父对象。父对象不是名称,而是另一个人对象!(有点像链表)。然后,您可以将人员集合保留为单个列表 解析文件时,您会不断将人员添加到列表中,同时使用正确的对象更新其子/父属性 之后,对于任何人,只需打印属性以查找关系即可 下面是一个可能的实现(在Python-2.6上)。本例中的文本文件仅包含这些关系。查询稍后使用交互式输入触发
class Person(object):
"""Information about a single name"""
def __init__(self,name):
self.name = name
self.parent = None
self.children = []
def search_people(people,name):
"""Searches for a name in known people and returns the corresponding Person object or None if not found"""
try:
return filter(lambda y: y.name == name,people)[0]
except IndexError:
return None
def search_add_and_return(people,name):
"""Search for a name in list of people. If not found add to people. Return the Person object in either case"""
old_name = search_people(people,name)
if old_name is None:
#First time entry for the name
old_name = Person(name)
people.append(old_name)
return old_name
def read_file(file_name,people):
fp = open(file_name,'r')
while True:
l = fp.readline()
l.strip('\n').strip()
if not l:
break
names = l.split(':')
mother = names[0].strip()
children = [x.strip() for x in names[1].split(',')]
old_mother = search_add_and_return(people,mother)
#Now get the children objects
child_objects = []
for child in children:
old_child = search_add_and_return(people,child)
child_objects.append(old_child)
#All children have been gathered. Link them up
#Set parent in child and add child to parent's 'children'
old_mother.children.extend(child_objects)
for c in child_objects:
c.parent = old_mother
fp.close()
def main():
file_name = 'try.txt'
people = []
read_file(file_name,people)
#Now lets define the language and start a loop
while True:
command = raw_input("Enter your command or 0 to quit\n")
if command == '0':
break
coms = command.split()
if len(coms) < 2:
print "Wrong Command"
continue
action = coms[0]
param = coms[1]
if action == "mother":
person = search_people(people,param)
if person == None:
print "person not found"
continue
else:
if person.parent is None:
print "mother not known"
else:
print person.parent.name
elif action == "ancestors":
person = search_people(people,param)
if person == None:
print "person not found"
continue
else:
ancestor_list = []
#Need to keep looking up parent till we don't reach a dead end
#And collect names of each ancestor
while True:
person = person.parent
if person is None:
break
ancestor_list.append(person.name)
if ancestor_list:
print ",".join(ancestor_list)
else:
print "No known ancestors"
if __name__ == '__main__':
main()
要查找父项,只需搜索名称是否在字典值中,如果找到,则返回键。如果没有找到母亲,则不返回任何母亲
mother = None
for k,v in relation_dict.items():
if name in v:
mother = k
break
return mother
如果你想找到所有的祖先,你只需要重复这个过程,直到没有返回
ancestor_list = []
person = name
while True:
person = find_parent(relation_dict,person)
if person == None:
#Top of the ancestor chain found
break
else:
ancestor_list.append(person)
下面是Python-2.6中的一个实现。它假定文本文件的结构是这样的:首先是所有关系,然后是空行,然后是所有命令
def read_file(file_name):
fp = open(file_name,'r')
relations = []
commands = []
reading_relations = True
for l in fp:
l = l.strip('\n')
if not l:
reading_relations = False
continue
if reading_relations:
relations.append(l.strip())
else:
commands.append(l.strip())
fp.close()
return relations,commands
def form_relation_dict(relations):
relation_dict = {}
for l in relations:
names = l.split(':')
mother = names[0].strip()
children = [x.strip() for x in names[1].split(',')]
existing_children = relation_dict.get(mother,[])
existing_children.extend(children)
relation_dict[mother] = existing_children
return relation_dict
def search_name(relation_dict,name):
#Returns True if name occurs anywhere in relation_dict
#Else return False
for k,v in relation_dict.items():
if name ==k or name in v:
return True
return False
def find_parent(relation_dict,param):
#Finds the parent of 'param' in relation_dict
#Returns None if no mother found
#Returns mother name otherwise
mother = None
for k,v in relation_dict.items():
if param in v:
mother = k
break
return mother
def process_commands(commands,relation_dict):
output = []
for c in commands:
coms = c.split()
if len(coms) < 2:
output.append("Invalid Command")
continue
action = coms[0]
param = coms[1]
if action == "mother":
name_found = search_name(relation_dict,param)
if not name_found:
output.append("person not found")
continue
else:
person = find_parent(relation_dict,param)
if person is None:
output.append("mother not known")
else:
output.append("mother - %s" %(person))
elif action == "ancestors":
name_found = search_name(relation_dict,param)
if not name_found:
output.append("person not found")
continue
else:
#Loop through to find the mother till dead - end (None) is not reached
ancestor_list = []
person = param
while True:
person = find_parent(relation_dict,person)
if person == None:
#Top of the ancestor found
break
else:
ancestor_list.append(person)
if ancestor_list:
output.append(",".join(ancestor_list))
else:
output.append("No known ancestors")
return output
def main():
file_name = 'try.txt'
relations,commands = read_file(file_name)
#Process Relqations to form a dictionary of the type {parent: [child1,child2,...]}
relation_dict = form_relation_dict(relations)
print relation_dict
#Now process commands in the file
output = process_commands(commands,relation_dict)
print '\n'.join(output)
if __name__ == '__main__':
main()
EDIT2
如果您真的想将其进一步拆分为函数,下面是process\u命令
的外观
def process_mother(relation_dict,name):
#Processes the mother command
#Returns the ouput string
output_str = ''
name_found = search_name(relation_dict,name)
if not name_found:
output_str = "person not found"
else:
person = find_parent(relation_dict,name)
if person is None:
output_str = "mother not known"
else:
output_str = "mother - %s" %(person)
return output_str
def process_ancestors(relation_dict,name):
output_str = ''
name_found = search_name(relation_dict,name)
if not name_found:
output_str = "person not found"
else:
#Loop through to find the mother till dead - end (None) is not reached
ancestor_list = []
person = name
while True:
person = find_parent(relation_dict,person)
if person == None:
#Top of the ancestor found
break
else:
ancestor_list.append(person)
if ancestor_list:
output_str = ",".join(ancestor_list)
else:
output_str = "No known ancestors"
return output_str
def process_commands(commands,relation_dict):
output = []
for c in commands:
coms = c.split()
if len(coms) < 2:
output.append("Invalid Command")
continue
action = coms[0]
param = coms[1]
if action == "mother":
new_output = process_mother(relation_dict,param)
elif action == "ancestors":
new_output = process_ancestors(relation_dict,param)
if new_output:
output.append(new_output)
return output
def进程(关系、名称):
#处理母命令
#返回输出字符串
输出_str=''
name\u found=搜索名称(关系、名称)
如果未找到名称,\u:
输出\u str=“未找到人员”
其他:
person=查找父对象(关系、名称)
如果此人没有:
输出
mother not known
Alice,Brenda,Sue
person not found
No known ancestors
def process_mother(relation_dict,name):
#Processes the mother command
#Returns the ouput string
output_str = ''
name_found = search_name(relation_dict,name)
if not name_found:
output_str = "person not found"
else:
person = find_parent(relation_dict,name)
if person is None:
output_str = "mother not known"
else:
output_str = "mother - %s" %(person)
return output_str
def process_ancestors(relation_dict,name):
output_str = ''
name_found = search_name(relation_dict,name)
if not name_found:
output_str = "person not found"
else:
#Loop through to find the mother till dead - end (None) is not reached
ancestor_list = []
person = name
while True:
person = find_parent(relation_dict,person)
if person == None:
#Top of the ancestor found
break
else:
ancestor_list.append(person)
if ancestor_list:
output_str = ",".join(ancestor_list)
else:
output_str = "No known ancestors"
return output_str
def process_commands(commands,relation_dict):
output = []
for c in commands:
coms = c.split()
if len(coms) < 2:
output.append("Invalid Command")
continue
action = coms[0]
param = coms[1]
if action == "mother":
new_output = process_mother(relation_dict,param)
elif action == "ancestors":
new_output = process_ancestors(relation_dict,param)
if new_output:
output.append(new_output)
return output