如何使用OAuth、python登录到站点？

所以我有一个脚本，需要访问一个需要通过OAuth登录的网站的功能

我已经从开发控制台获得了一个OAuth客户端机密文件——现在我的脚本可以成功地检索用户的youtube视频列表——这就是我现在拥有的

__author__ = 'anish'

import httplib2
import sys

from googleapiclient.discovery import build
from oauth2client.client import flow_from_clientsecrets
from oauth2client.file import Storage
from oauth2client.tools import argparser, run_flow

import requests
from requests_oauthlib import OAuth1Session

# Most of the code is sourced from https://developers.google.com/youtube/v3/guides/uploading_a_video

CLIENT_SECRETS_FILE = "client_secrets.json"

YOUTUBE_READ_WRITE_SCOPE = "https://www.googleapis.com/auth/youtube"
YOUTUBE_API_SERVICE_NAME = "youtube"
YOUTUBE_API_VERSION = "v3"

MISSING_CLIENT_SECRETS_MESSAGE = "Missing client secrets"

def get_credentials(args):
    flow = flow_from_clientsecrets(CLIENT_SECRETS_FILE, scope=YOUTUBE_READ_WRITE_SCOPE)
    storage = Storage("%s-oauth2.json" % sys.argv[0])
    credentials = storage.get()

    if credentials is None or credentials.invalid:
        credentials = run_flow(flow, storage, args)

    return credentials

def videos(youtube, uid):
    initial = youtube.playlistItems().list(part="snippet", maxResults=50,
                                           playlistId="UUy2Lh8b-y0r-35LlcjOPPzw").execute()
    yield initial
    while "nextPageToken" in initial:
        initial = youtube.playlistItems().list(part="snippet", maxResults=50,
                                           playlistId="UUy2Lh8b-y0r-35LlcjOPPzw",
                                           pageToken=initial["nextPageToken"]).execute()
        yield initial

if __name__ == "__main__":

    video_list = []

    http = get_credentials(argparser.parse_args()).authorize(httplib2.Http())

    rq = http.request("http://github.com", method="GET")
    print(rq[1])

    youtube = build(YOUTUBE_API_SERVICE_NAME, YOUTUBE_API_VERSION,
        http=http)

    info = youtube.channels().list(part="contentDetails", forUsername="IndianaRobotics").execute()
    uploads_id = info["items"][0]["contentDetails"]["relatedPlaylists"]["uploads"]

    for v in videos(youtube, uploads_id):
        for item in v["items"]:
            video_list.append([item["snippet"]["title"], item["snippet"]["resourceId"]["videoId"]])

    for v_info in video_list:
        print(v_info)

因此，我的访问令牌谷歌API的作品。然而，当我做这样的事情时

print(http.request("http://github.com", method="GET")

虽然我使用OAuth登录github，并且我拥有的凭据来自我的帐户，但我还是得到了登录页面作为响应

---

有没有办法使用我必须登录到github这样的站点的

http

对象？我需要在没有来自站点本身的任何API的情况下访问它，因为我想要与之交互的站点没有OAuth的API

，而您可以使用

oauth2client

获取实现OAuth2（包括github）的站点的凭据，这对于没有API或实现OAuth2的站点是不起作用的。