Python 如何在beautifulsoup4中根据图像中的内容分离图像链接

我是新来的BeautifulSoup4，我试图从一个网站获取所有图片链接，例如Unsplash，但我只想在url中包含单词“photo”的url，例如

我不希望URL包含单词“个人资料”，例如

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我正在使用Pyhton 3.6和urllib3。您可以使用此脚本作为示例，如何筛选链接：

import requests
from bs4 import BeautifulSoup


url = 'https://unsplash.com'
soup = BeautifulSoup(requests.get(url).content, 'html.parser')

for img in soup.find_all('img'):
    if 'photo' in img['src']:  # print only links with `photo` inside them
        print(img['src'])

印刷品：

https://images.unsplash.com/photo-1597649260558-e2bd7d35f043?ixlib=rb-1.2.1&ixid=eyJhcHBfaWQiOjEyMDd9&auto=format%2Ccompress&fit=crop&w=1000&h=1000
https://images.unsplash.com/photo-1598929214025-d6bb6167d43b?ixlib=rb-1.2.1&ixid=eyJhcHBfaWQiOjEyMDd9&w=1000&q=80
https://images.unsplash.com/photo-1599567513879-604247ea2bd3?ixlib=rb-1.2.1&ixid=eyJhcHBfaWQiOjEyMDd9&w=1000&q=80
https://images.unsplash.com/photo-1599366611308-719895c34512?ixlib=rb-1.2.1&ixid=eyJhcHBfaWQiOjEyMDd9&w=1000&q=80
https://images.unsplash.com/photo-1598929214025-d6bb6167d43b?ixlib=rb-1.2.1&ixid=eyJhcHBfaWQiOjEyMDd9&w=1000&q=80
https://images.unsplash.com/photo-1599366611308-719895c34512?ixlib=rb-1.2.1&ixid=eyJhcHBfaWQiOjEyMDd9&w=1000&q=80
https://images.unsplash.com/photo-1599567513879-604247ea2bd3?ixlib=rb-1.2.1&ixid=eyJhcHBfaWQiOjEyMDd9&w=1000&q=80
https://images.unsplash.com/photo-1598929214025-d6bb6167d43b?ixlib=rb-1.2.1&ixid=eyJhcHBfaWQiOjEyMDd9&w=1000&q=80
https://images.unsplash.com/photo-1599567513879-604247ea2bd3?ixlib=rb-1.2.1&ixid=eyJhcHBfaWQiOjEyMDd9&w=1000&q=80
https://images.unsplash.com/photo-1599366611308-719895c34512?ixlib=rb-1.2.1&ixid=eyJhcHBfaWQiOjEyMDd9&w=1000&q=80

---

使用

urllib

：

import urllib.request
from bs4 import BeautifulSoup


url = 'https://unsplash.com'
soup = BeautifulSoup(urllib.request.urlopen(url).read(), 'html.parser')

for img in soup.find_all('img'):
    if 'photo' in img['src']:
        print(img['src'])

---

你可以简单地把它们全部取出来，然后过滤掉代码中不需要的部分。你能用代码添加一个例子吗，因为我对它不熟悉。Andrej Kesely说了很多