Python 如何使用Django通过链接呈现与一个条目关联的所有数据？

我正在学习Django，并创建了一个应用程序“myapp”，具有不同的组件，如下所示：

模型如下所示： Model.py：

from __future__ import unicode_literals
from django.db import models

class Country(models.Model):
    name = models.CharField(max_length=200)

    def __unicode__(self):
        return self.name


class CountryDetails(models.Model):
    country = models.ForeignKey(Country)
    T_attack = models.PositiveIntegerField(verbose_name="attack")
    year = models.CharField(max_length=254)
    Deaths = models.CharField(max_length=254)
    NEWS_ID = models.CharField(max_length=254, verbose_name="NEWS_ID")


    def __unicode__(self):
        return self.Deaths

视图如下所示： view.py：

from django.shortcuts import render, get_object_or_404
from .models import Country, CountryDetails 

def home(request):
    c_list = Country.objects.all()
    return render(request, 'myapp/home.html', {'c_list':c_list})

def details(request, pk):
    c_details =  get_object_or_404(CountryDetails, pk)
    return render(request, 'myapp/home.html', {'c_details':c_details})

URL如下所示： URL.py：

“myapp”的“Home.html”显示所有可用国家/地区的列表，如下所示：

INDIA 
PKISTAN
USA
CANADA

我希望，当我单击时，让我们假设在印度，它应该在第二个“html”页面上呈现所有可用的详细信息，比如“detailed.html”，与印度相关，如下所示：

name   T_attack   year  Deaths  News_ID
India    12       2006   12       NDTV
India    110      2009   1        DEAN
India    12       2023   120      NDNV
India    10       2012   12       DEAN

但是，当我执行代码时，它会显示如下错误：

ValueError at /myapp/1/
need more than 1 value to unpack
Request Method: GET
Request URL:    http://127.0.0.1:8000/myapp/1/
Django Version: 1.10
Exception Type: ValueError
Exception Value:    
need more than 1 value to unpack
Exception Location: /home/jai/Desktop/trytable/local/lib/python2.7/site-packages/django/db/models/sql/query.py in build_filter, line 1130
Python Executable:  /home/jai/Desktop/trytable/bin/python
Python Version: 2.7.6
Python Path:    
['/home/jai/Desktop/trytable/test_project',
 '/home/jai/Desktop/trytable/lib/python2.7',
 '/home/jai/Desktop/trytable/lib/python2.7/plat-i386-linux-gnu',
 '/home/jai/Desktop/trytable/lib/python2.7/lib-tk',
 '/home/jai/Desktop/trytable/lib/python2.7/lib-old',
 '/home/jai/Desktop/trytable/lib/python2.7/lib-dynload',
 '/usr/lib/python2.7',
 '/usr/lib/python2.7/plat-i386-linux-gnu',
 '/usr/lib/python2.7/lib-tk',
 '/home/jai/Desktop/trytable/local/lib/python2.7/site-packages',
 '/home/jai/Desktop/trytable/lib/python2.7/site-packages']
Server time:    Sat, 15 Jul 2017 16:03:33 +0000

请帮帮我。谢谢

c_details =  get_object_or_404(CountryDetails, pk) 

你应该把它换成

c_details = CountryDetails.objects.filter(country__pk=pk)

在您的URL中，您使用的是国家的

pk

，因此您需要筛选与国家相关的所有行。

过滤器

查询就是这样做的。 要在模板中显示详细信息，可以执行以下操作

{% for c in c_details %}

 <h1>{{ c.T_attack }}</h3></br>
 <!-- and so on for the other fields also. -->

{% endfor %}

{%forc-in-c\u-details%}
{{c.T_攻击}

{%endfor%}

使用

c_details

的模板代码在哪里？@AlexHall，我认为在列表中它应该返回一些要渲染的内容，所以我现在不能为此写任何东西，你能告诉我它看起来像bcz吗，因为我只在Django上工作了三天，现在我的大脑不允许我理解。我已经尝试并探索了互联网上的所有教程和帖子，我的一切都不起作用。Greatttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttt您可以使用

\uu

对外键类的属性进行筛选<代码>国家/地区是外键。它不能与任何东西一起使用。感谢您的解释和回答：）

c_details =  get_object_or_404(CountryDetails, pk) 

c_details = CountryDetails.objects.filter(country__pk=pk)

{% for c in c_details %}

 <h1>{{ c.T_attack }}</h3></br>
 <!-- and so on for the other fields also. -->

{% endfor %}