Python 如何根据条件验证数据
我想限制用户的输入,这样它只接受0到90之间的整数。如果您想限制sum变量,只需在代码末尾放一个If语句,检查变量是否在边界内即可Python 如何根据条件验证数据,python,python-2.7,python-3.x,Python,Python 2.7,Python 3.x,我想限制用户的输入,这样它只接受0到90之间的整数。如果您想限制sum变量,只需在代码末尾放一个If语句,检查变量是否在边界内即可 a = int(input("Enter mark of BIOLOGY: ")) b = int(input("Enter mark of CHEMISTRY: ")) c = int(input("Enter mark of PHYSICS: ")) sum = a + b + c x = sum y = 3 avg = x / y print("To
a = int(input("Enter mark of BIOLOGY: "))
b = int(input("Enter mark of CHEMISTRY: "))
c = int(input("Enter mark of PHYSICS: "))
sum = a + b + c
x = sum
y = 3
avg = x / y
print("Total marks = ", sum)
print("Average marks = ", avg)
如果总和>90:
总和=90
elif总和<0:
总和=0
要将用户的输入限制在0到90,您需要反复要求用户重新输入数据,直到数据满足0到90的标准。您可以通过实现while
循环,然后break
来实现这一点,前提是满足条件。代码如下:
if sum > 90:
sum = 90
elif sum < 0:
sum = 0
#变量“a”的数据验证
尽管如此:
a=int(输入(“输入生物学标记:”)
如果0以下代码将确保用户输入指定范围内的数字:
# Data validation for the variable "a"
while True:
a = int(input("Enter mark of BIOLOGY: "))
if 0 <= a <= 90:
break
else:
print("The mark is not between 0 and 90. Please enter a new mark.")
为True时:
a=int(输入(“输入生物学标记=”))
如果为0,尽管这可能有效,但如果用户无意中将分数置于0到90的范围之外,该怎么办?反复询问用户imho更安全。这完全取决于代码的用途,询问者没有提供太多信息。我确实看到你的建议很可能是用户提问时的意思。
while True:
a = int(input("enter mark of BIOLOGY = "))
if 0 <= a <= 90:
break
else:
print("Invalid mark. Please try again.")
while True:
b = int(input("enter mark of CHEMISTRY = "))
if 0 <= b <= 90:
break
else:
print("Invalid mark. Please try again.")
while True:
c = int(input("enter mark of PHYSICS = "))
if 0 <= c <= 90:
break
else:
print("Invalid mark. Please try again.")
sum = a + b + c
x = sum
y = 3
avg = x / y
print("total marks = ", sum)
print("average marks = ", avg)