Python 2.7 BeautifulSoup Python如何在函数中以列表形式返回for循环中的所有值

我有一个带for循环的函数。它遍历列表并将每个值打印到控制台。
我想在函数的末尾放一个return语句，这样当我调用函数时，就可以返回所有的值。 我想我需要把它作为一个列表返回

我的职能是：

def extract_header_from_summary_from_report_htmltestrunner():
    filename = (r"C:\temp\selenium_report\ClearCore501_Automated_GUI_TestReport.html")    html_report_part = open(filename,'r')
    soup = BeautifulSoup(html_report_part, "html.parser")
    table = soup.select_one("#result_table")
    headers = [td.text for td in table.select_one("#header_row").find_all("td")[1:-1]]
    print(" ".join(headers))
    for row in table.select("tr.passClass"):
        print(" ".join([td.text for td in row.find_all("td")[1:-1]]))

如何将返回放在末尾，并从for循环返回每个值

for循环打印出以下内容：

Count Pass Fail Error
75 75 0 0

---

谢谢，Riaz是什么阻止了你创建一个空列表并附加到它上面的呢

def extract_header_from_summary_from_report_htmltestrunner():
    filename = (r"C:\temp\selenium_report\ClearCore501_Automated_GUI_TestReport.html")    html_report_part = open(filename,'r')
    soup = BeautifulSoup(html_report_part, "html.parser")
    table = soup.select_one("#result_table")

    #Create list here...
    results = []

    headers = [td.text for td in table.select_one("#header_row").find_all("td")[1:-1]]
    print(" ".join(headers))

    #Don't forget to append header (if you want)
    results.append(headers)

    for row in table.select("tr.passClass"):
        #Store row string in variable and append before printing
        row_str = " ".join([td.text for td in row.find_all("td")[1:-1]]))
        results.append(row_str)
        print(row_str)

    return results

---

您可以生成每个字符串：

from bs4 import BeautifulSoup

def extract_header_from_summary_from_report_htmltestrunner():
    filename = (r"C:\temp\selenium_report\ClearCore501_Automated_GUI_TestReport.html")    html_report_part = open(filename,'r')
    soup = BeautifulSoup(html_report_part, "html.parser")
    table = soup.select_one("#result_table")
    headers = [td.text for td in table.select_one("#header_row").find_all("td")[1:-1]]
    yield (" ".join(headers))
    for row in table.select("tr.passClass"):
        yield " ".join([td.text for td in row.find_all("td")[1:-1]])

然后调用

列表（从\u摘要中提取\u头\u从\u报告中提取\u htmlestrunner（））

或迭代生成器函数：

for row in extract_header_from_summary_from_report_htmltestrunner():
   # use each row