基于特定值连接的Python词典列表

我确实有一本字典的目录

list_dict=[{'date':'24-01-2017','amount':12.0},{'date':'24-01-2017','amount':23.0},
{'date':'24-01-2017','amount':2.0},{'date':'25-01-2017','amount':10.0},{'date':'25-01-2017','amount':3.0},
{'date':'26-01-2017','amount':2.0}]

我需要像这样的输出

new_dict=[{'total':27.0,[{'date':'24-01-2017','amount':12.0},{'date':'24-01-2017','amount':23.0},
{'date':'24-01-2017','amount':2.0},],[{'total':13.0,{'date':'25-01-2017','amount':10.0},{'date':'25-01-2017','amount':3.0}],[{'total':2.0,
{'date':'26-01-2017','amount':2.0}]]

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如何在python中执行此操作？

您的输出不正确，因为您需要一个包含列表的dict，但您可以有如下内容：

dates = list(set([item['date'] for item in list_dict]))
result = [[{'total': sum([item['amount'] for item in list_dict if item['date'] == date])}, [{k: v} for value in list_dict for k, v in value.items() if value['date'] == date]] for date in dates]

[{'total': 13.0}, [{'date': '25-01-2017'}, {'amount': 10.0}, {'date': '25-01-2017'}, {'amount': 3.0}]]
[{'total': 37.0}, [{'date': '24-01-2017'}, {'amount': 12.0}, {'date': '24-01-2017'}, {'amount': 23.0}, {'date': '24-01-2017'}, {'amount': 2.0}]]
[{'total': 2.0}, [{'date': '26-01-2017'}, {'amount': 2.0}]]

结果如下所示：

dates = list(set([item['date'] for item in list_dict]))
result = [[{'total': sum([item['amount'] for item in list_dict if item['date'] == date])}, [{k: v} for value in list_dict for k, v in value.items() if value['date'] == date]] for date in dates]

[{'total': 13.0}, [{'date': '25-01-2017'}, {'amount': 10.0}, {'date': '25-01-2017'}, {'amount': 3.0}]]
[{'total': 37.0}, [{'date': '24-01-2017'}, {'amount': 12.0}, {'date': '24-01-2017'}, {'amount': 23.0}, {'date': '24-01-2017'}, {'amount': 2.0}]]
[{'total': 2.0}, [{'date': '26-01-2017'}, {'amount': 2.0}]]

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请更明确地说明您想要实现的目标，并向我们展示您的目标。那么，您可以使用熊猫吗？它看起来是适合这个的工具