Python：通过引用传递套接字

我是python新手，我必须用python编写我的第一个任务。我保证在我完成这件事后我会从里到外学习，但我现在需要你的帮助

我的代码当前如下所示：

comSocket.send("\r")
sleep(1)
comSocket.send("\r")
sleep(2)
comSocket.settimeout(8)
try:
   comSocket.recv(256)
except socket.timeout:
   errorLog("[COM. ERROR] Station took too long to reply. \n")
   comSocket.shutdown(1)
   comSocket.close()
   sys.exit(0)

comSocket.send("\r\r")
sleep(2)
comSocket.settimeout(8)
try:
   comSocket.recv(256)
except socket.timeout:
   errorLog("[COM. ERROR] Station took too long to reply. \n")
   comSocket.shutdown(1)
   comSocket.close()
   sys.exit(0)

class ComunicationSocket(socket):
    def errorLog(self, message):
        # in this case, self it's an instance of your object comSocket, 
        # therefore your "reference"
        # place the content of errorLog function
        return True # Here you return what you received from socket

errorLog

是另一种方法。我想通过创建一个新方法重写此代码，这样我就可以传递

消息

，引用

套接字

，然后

返回从套接字接收到的内容

有什么帮助吗

谢谢：）
猜猜你想要什么：

def send_and_receive(message, socket):
    socket.send(message)
    return socket.recv(256) # number is timeout

然后将您的
try:except:
放在调用此方法的周围。
您应该创建一个类来管理您的错误，该类需要扩展您用于comSocket实例的类，在该类中放置errorLog函数。
大概是这样的：

comSocket.send("\r")
sleep(1)
comSocket.send("\r")
sleep(2)
comSocket.settimeout(8)
try:
   comSocket.recv(256)
except socket.timeout:
   errorLog("[COM. ERROR] Station took too long to reply. \n")
   comSocket.shutdown(1)
   comSocket.close()
   sys.exit(0)

comSocket.send("\r\r")
sleep(2)
comSocket.settimeout(8)
try:
   comSocket.recv(256)
except socket.timeout:
   errorLog("[COM. ERROR] Station took too long to reply. \n")
   comSocket.shutdown(1)
   comSocket.close()
   sys.exit(0)

class ComunicationSocket(socket):
    def errorLog(self, message):
        # in this case, self it's an instance of your object comSocket, 
        # therefore your "reference"
        # place the content of errorLog function
        return True # Here you return what you received from socket

现在，您只需使用它的实例化ComCommunicationSocket即可：

comSocket = ComunicationSocket()
try:
    comSocket.recv(256)
except socket.timeout:
    # Uses the instance of comSocket to log the error
    comSocket.errorLog("[COM. ERROR] Station took too long to reply. \n")
    comSocket.shutdown(1)
    comSocket.close()
    sys.exit(0)

希望有帮助，你没有发布函数错误日志的内容，所以我在你应该放的地方放了一条评论。这是一种做事的方式。希望有帮助。
一个简单的解决方案是

def socketCom(comSocket, length, message, time):
    comSocket.send(message)
    comSocket.settimeout(8)
    if (time != 0):
        sleep(time)
    try:
        rawData = comSocket.recv(length)
    except socket.timeout:
        errorLog("[COM. ERROR] Station took too long to reply. \n")
        comSocket.shutdown(1)
        comSocket.close()
        sys.exit(0)

    return rawData

\r\r
是一条消息：）消息可以是任意长度的字符串。我知道如何定义函数/方法。我想通过
socket
作为参考。哦，你也可以使用decorators，如果我的建议有用，请告诉我，或者我们可以尝试其他方法。