Python 如何在每5行之后在pandas数据框中添加新id,
如何在每5行之后在pandas数据框中添加新id 所以我的数据是:Python 如何在每5行之后在pandas数据框中添加新id,,python,python-3.x,pandas,Python,Python 3.x,Pandas,如何在每5行之后在pandas数据框中添加新id 所以我的数据是: index DateTime A1 A2 A4 AMS baseD 16610745 2011-01-03T13:15:00 130 122 368010037 128 003669730 16610745 2011-01-03T13:15:00 130 122 368010037 128 003669730 16610747
index DateTime A1 A2 A4 AMS baseD
16610745 2011-01-03T13:15:00 130 122 368010037 128 003669730
16610745 2011-01-03T13:15:00 130 122 368010037 128 003669730
16610747 2011-01-03T13:15:59 112 103 368010037 128 003669730
16610749 2011-01-03T13:17:00 95 90 368010037 128 003669730
16610751 2011-01-03T13:18:00 75 67 368010037 128 003669730
16610753 2011-01-03T13:18:59 42 33 368010037 128 003669730
16610755 2011-01-03T13:20:00 14 7 368010037 128 003669794
16610745 2011-01-03T13:15:00 130 122 368010037 128 003669730
16610745 2011-01-03T13:15:00 130 122 368010037 128 003669730
16610747 2011-01-03T13:15:59 112 103 368010037 128 003669730
16610749 2011-01-03T13:17:00 95 90 368010037 128 003669730
16610751 2011-01-03T13:18:00 75 67 368010037 128 003669730
16610753 2011-01-03T13:18:59 42 33 368010037 128 003669730
16610755 2011-01-03T13:20:00 14 7 368010037 128 003669794
我需要的是一个ID列,它每5行递增一次
index DateTime A1 A2 A4 AMS baseD ID
16610745 2011-01-03T13:15:00 130 122 368010037 128 003669730 1
16610745 2011-01-03T13:15:00 130 122 368010037 128 003669730 1
16610747 2011-01-03T13:15:59 112 103 368010037 128 003669730 1
16610749 2011-01-03T13:17:00 95 90 368010037 128 003669730 1
16610751 2011-01-03T13:18:00 75 67 368010037 128 003669730 1
16610753 2011-01-03T13:18:59 42 33 368010037 128 003669730 2
16610755 2011-01-03T13:20:00 14 7 368010037 128 003669794 2
16610745 2011-01-03T13:15:00 130 122 368010037 128 003669730 2
16610745 2011-01-03T13:15:00 130 122 368010037 128 003669730 2
16610747 2011-01-03T13:15:59 112 103 368010037 128 003669730 2
16610749 2011-01-03T13:17:00 95 90 368010037 128 003669730 3
16610751 2011-01-03T13:18:00 75 67 368010037 128 003669730 3
16610753 2011-01-03T13:18:59 42 33 368010037 128 003669730 3
16610755 2011-01-03T13:20:00 14 7 368010037 128 003669794 3
16610755 2011-01-03T13:20:00 14 7 368010037 128 003669794 3
您可以生成1,2,3…的序列,。。。。对于第5%的数据帧行,重复(np.repeat)每个值5次,并分配为
ID
:-)
每5行(不是列)递增OHH是的,对不起,它的行我将编辑我的问题,谢谢谢谢:-)@pyd
df['id'] = np.repeat(np.arange(np.ceil(len(df)/5),5)[:len(df)]