条件列表Python

我打开zip中存在的所有文件，然后将字符串转换为列表，然后将列表从每行分解为5个元素

我的代码：

with zipfile.ZipFile(dummy.zip, 'r') as mz:
    for f in mz.namelist():
        data = mz.read(f).decode('utf-8').replace("\n", '').replace("\r", ',').lstrip().rstrip().split(",") #Removing all spaces and \r from text.
        allist = [data[i:i + 5] for i in range(len(data))[::5]] #breaking list into 5 elements each

Yuli, yu@test.com, 0001, 8902
Su, su@test.com, 0002, 8903, Manager

如果所有的值都存在的话，我可以做得很好，但是如果在特定的行中缺少任何元素，那么它会从第二行中拾取值，但是我想在缺少元素的位置添加

NA

文件数据： Dummy.zip=“File1+File2”

文件1:

with zipfile.ZipFile(dummy.zip, 'r') as mz:
    for f in mz.namelist():
        data = mz.read(f).decode('utf-8').replace("\n", '').replace("\r", ',').lstrip().rstrip().split(",") #Removing all spaces and \r from text.
        allist = [data[i:i + 5] for i in range(len(data))[::5]] #breaking list into 5 elements each

Yuli, yu@test.com, 0001, 8902
Su, su@test.com, 0002, 8903, Manager

文件：2

Zaon, zn@test.com, 100, 9087, Analyst
June, ju@test.com, 278, 6078

代码的目的：

with zipfile.ZipFile(dummy.zip, 'r') as mz:
    for f in mz.namelist():
        data = mz.read(f).decode('utf-8').replace("\n", '').replace("\r", ',').lstrip().rstrip().split(",") #Removing all spaces and \r from text.
        allist = [data[i:i + 5] for i in range(len(data))[::5]] #breaking list into 5 elements each

Yuli, yu@test.com, 0001, 8902
Su, su@test.com, 0002, 8903, Manager

---

我正在添加将此列表转换为dict，因此在每个条目中添加键，如姓名、电子邮件、分机、Empid、级别

您可以这样做：

texts = [b"Yuli, yu@test.com, 0001, 8902\r\nSu, su@test.com, 0002, 8903, Manager",
         b"Zaon, zn@test.com, 100, 9087, Analyst\r\nJune, ju@test.com, 278, 6078"]

result =[]
keys = "name,email,ext,Empid,Level".split(",")
# you do: 
# with zipfile.ZipFile(dummy.zip, 'r') as mz: 
#     for f in mz.namelist(): 
#         t = mz.read(f) here instead
# instead
for t in texts:
    for line in t.decode("utf-8").split("\n"):
        d = {k:"NA" for k in keys} # init all keys with NA
        # update with actual values
        d.update(zip(keys,(l.strip() for l in line.strip().split(","))))
        # add to result list
        result.append(d) 
print(result)

输出：

[{'name': 'Yuli', 'email': 'yu@test.com', 'ext': '0001', 'Empid': '8902', 'Level': 'NA'}, 
 {'name': 'Su', 'email': 'su@test.com', 'ext': '0002', 'Empid': '8903', 'Level': 'Manager'},
 {'name': 'Zaon', 'email': 'zn@test.com', 'ext': '100', 'Empid': '9087', 'Level': 'Analyst'}, 
 {'name': 'June', 'email': 'ju@test.com', 'ext': '278', 'Empid': '6078', 'Level': 'NA'}]

---

将文件内容拆分为几行，然后在这些行上循环，而不是将整个文件视为一个简单的列表。@barmar感谢您的建议，我尝试过这样做，但在代码中迷失了方向。有什么建议吗？

使用mz.open（f）作为文件：

然后像处理普通文件一样处理它。您甚至可以使用

csv

模块来解析它。然后您可以使用

readline（）

或

等函数来解析文件中的行：