Python 将多个词典读入嵌套列表
我正在计数器中读取下面的列表,我想将所有键分组到一个嵌套列表中,如下所示Python 将多个词典读入嵌套列表,python,python-3.x,list,dictionary,Python,Python 3.x,List,Dictionary,我正在计数器中读取下面的列表,我想将所有键分组到一个嵌套列表中,如下所示 import collections A=["cool","lock","cook"] B=[] d={} for i in A: B.append(collections.Counter(i)) print(B) ## B value is [Counter({'o': 2, 'c': 1, 'l': 1}), Counter({'l': 1, 'o'
import collections
A=["cool","lock","cook"]
B=[]
d={}
for i in A:
B.append(collections.Counter(i))
print(B)
## B value is [Counter({'o': 2, 'c': 1, 'l': 1}), Counter({'l': 1, 'o': 1, 'c': 1, 'k': 1}), Counter({'o': 2, 'c': 1, 'k': 1})]
for i in B:
for j in i.keys():
d.setdefault( d[j],[]).append(i.values())
print(d)
我遇到一个关键错误,我使用了Setdefault()
,但能够使其正常工作
所需产出:
{'o':[2,1,2],'c':[1,1,1],'l':[1,1],'k':[1,1] }
以下是如何:
import collections
A = ["cool", "lock", "cook"]
B = []
d = {}
for i in A:
B.append(collections.Counter(i))
for i in B:
for j in i:
if j in d:
d[j].append(i[j])
else:
d[j] = [i[j]]
print(d)
输出:
{'c': [1, 1, 1], 'o': [2, 1, 2], 'l': [1, 1], 'k': [1, 1]}
您甚至可以在定义
B
时使用map
来提高效率:
import collections
A = ["cool", "lock", "cook"]
B = map(collections.Counter, A)
d = {}
for i in B:
for j in i:
if j in d:
d[j].append(i[j])
else:
d[j] = [i[j]]
print(d)