Python 将多个词典读入嵌套列表

Python 将多个词典读入嵌套列表,python,python-3.x,list,dictionary,Python,Python 3.x,List,Dictionary,我正在计数器中读取下面的列表,我想将所有键分组到一个嵌套列表中,如下所示 import collections A=["cool","lock","cook"] B=[] d={} for i in A: B.append(collections.Counter(i)) print(B) ## B value is [Counter({'o': 2, 'c': 1, 'l': 1}), Counter({'l': 1, 'o'

我正在计数器中读取下面的列表,我想将所有键分组到一个嵌套列表中,如下所示

import collections
A=["cool","lock","cook"]
B=[]
d={}
for i in A:
    B.append(collections.Counter(i))
print(B)

## B value is [Counter({'o': 2, 'c': 1, 'l': 1}), Counter({'l': 1, 'o': 1, 'c': 1, 'k': 1}), Counter({'o': 2, 'c': 1, 'k': 1})]
for i in B:
    for j in i.keys():
         d.setdefault( d[j],[]).append(i.values())
print(d)
我遇到一个关键错误,我使用了
Setdefault()
,但能够使其正常工作

所需产出:

{'o':[2,1,2],'c':[1,1,1],'l':[1,1],'k':[1,1] }
以下是如何:

import collections

A = ["cool", "lock", "cook"]
B = []
d = {}
for i in A:
    B.append(collections.Counter(i))
    
for i in B:
    for j in i:
        if j in d:
            d[j].append(i[j])
        else:
            d[j] = [i[j]]
print(d)
输出:

{'c': [1, 1, 1], 'o': [2, 1, 2], 'l': [1, 1], 'k': [1, 1]}

您甚至可以在定义
B
时使用
map
来提高效率:

import collections

A = ["cool", "lock", "cook"]
B = map(collections.Counter, A)
d = {}

for i in B:
    for j in i:
        if j in d:
            d[j].append(i[j])
        else:
            d[j] = [i[j]]
print(d)