在电子邮件密码检查器（python）中循环不工作时

此脚本的目标是询问用户他们的电子邮件和密码，如果不正确，则使用while循环，它应不断询问用户的详细信息，直到用户提供正确的电子邮件和密码

---

即使我第一次输入正确的电子邮件/密码，它也不起作用。

带有更正的代码

users = {
1: {"first_name": "Tom", "last_name": "Smith", "email": "tom@email.com", "password": "123123"},

2: {"first_name": "Simon", "last_name": "Stevens", "email": "simon@email.com", "password": "password1234"},

3: {"first_name": "Laura", "last_name": "Laurens", "email": "laura@email.com", "password": "laura1234"},

4: {"first_name": "Gabriel", "last_name": "Mitchel", "email": "gab@email.com", "password": "laura12534"}
}

email_input = input("What's your email?")
password_input = input("What's your password?")

for key, info in users.items():
    name = info["first_name"]
    last_name = info["last_name"]
    email = info["email"]
    password = info["password"]

while email_input != email and password_input != password:
    print("wrong password/email")
    email_input = input("What's your email?")
    password_input = input("What's your password?")    
print("You're logged in",name)

---

您的

和

应该是

或

。您只是将用户输入与

用户

字典中的最后一个用户名和密码进行比较，以防不明显。

users = {
    1: {"first_name": "Tom", "last_name": "Smith", "email": "tom@email.com", "password": "123123"},

    2: {"first_name": "Simon", "last_name": "Stevens", "email": "simon@email.com", "password": "password1234"},

    3: {"first_name": "Laura", "last_name": "Laurens", "email": "laura@email.com", "password": "laura1234"},

    4: {"first_name": "Gabriel", "last_name": "Mitchel", "email": "gab@email.com", "password": "laura12534"}
}


found = False
while not found:                                # loop until match found
    # Get login credentials
    email_input = input("What's your email?")
    password_input = input("What's your password?") 
    
    # check each dictionary for email and password
    for key, info in users.items():
        if email_input == info["email"] and password_input == info["password"]:
            # Found match, so get name
            name = info["first_name"]            
            last_name = info["last_name"]        
            found = True                        # set flag to terminate while loop
            break                               # found match
    else:
        print("wrong password/email")           # Break not encountered in for loop, so did not find match

print(f"You're logged in {name} {last_name}")