Python 使用Flask RESTful处理分层URI

我想要一个RESTful api，如下所示：

example.com/teams/
example.com/teams/<team_id>
example.com/teams/<team_id>/players
example.com/teams/<team_id>/players/<player_id>
...
example.com/teams/<team_id>/players/<player_id>/seasons/<season_id>/etc

并使用：

api.add_resource(Team, '/teams/', 'teams/<team_id>/players/<player_id>')

api.add_资源（团队，“/teams/”，“teams//players/”）

这将不起作用，因为后续的POST处理程序将覆盖前一个

使用Flask RESTful处理URL中可能存在变量数量可变（层次结构深度可变）的API的正确方法是什么？

Python不支持以这种特定方式进行方法重载。在代码中，您不是在重载

post（）

函数，而是在重新定义它

基本上，

post（）

class Team(Resource):
    def post(self, team_id, player_id):
        # This is the final definition of post()
        # The definitions above this one do not take effect

否则，使用具有参数默认值的单个方法很容易获得行为：

class Team(Resource):
    def post(self, team_id=None, player_id=None):
        if team_id is None and player_id is None:
            # first version
        if team_id is not None and player_id is None:
            # second version 
        if team_id is not None and player_id is not None:
            # third version

对于您的URL，Flask将为URL中未定义的参数传入
None
。
我看到的问题是，它没有区分
团队//players
和
团队///code>。有什么想法吗？
class Team(Resource):
    def post(self, team_id=None, player_id=None):
        if team_id is None and player_id is None:
            # first version
        if team_id is not None and player_id is None:
            # second version 
        if team_id is not None and player_id is not None:
            # third version