Python 使用包含列表的列重塑数据帧

假设我有一个数据帧，看起来像这样：

import pandas as pd

data = [{"Name" : "Project A", "Feedback" : ['we should do x', 'went well']},
            {"Name" : "Project B", "Feedback" : ['eat pop tarts', 'boo']},
            {"Name" : "Project C", "Feedback" : ['bar', 'baz']}
            ]

df = pd.DataFrame(data)
df = df[['Name','Feedback']]
df

    Name        Feedback
0   Project A   ['we should do x', 'went well']
1   Project B   ['eat pop tarts', 'boo']
2   Project C   ['bar', 'baz']

我想做的是重塑dataframe，这样Name就是关键，Feedback列列表中的每个元素都是这样的值：

        Name          Feedback
0       Project A    'we should do x'   
1       Project A    'went well'
2       Project B    'eat pop tarts'
3       Project B    'boo'
4       Project C    'bar'
5       Project C    'baz'

---

这样做的有效方法是什么

一个选项是通过展平列反馈并重复列名来重建数据帧：

---

一个选项是通过展平列反馈并重复列名来重建数据帧：

下面是另一种方法：

# Separate out values (NOTE- this assumes you'll always have two strings in list)
df['pos_0'] = df['Feedback'].str[0]
df['pos_1'] = df['Feedback'].str[1]

df
        Name                     Feedback           pos_0      pos_1
0  Project A  [we should do x, went well]  we should do x  went well
1  Project B         [eat pop tarts, boo]   eat pop tarts        boo
2  Project C                   [bar, baz]             bar        baz

期望输出：

pd.melt(df, 'Name', ['pos_0', 'pos_1'], 'Feedback').drop('Feedback', axis=1)
        Name           value
0  Project A  we should do x
1  Project B   eat pop tarts
2  Project C             bar
3  Project A       went well
4  Project B             boo
5  Project C             baz

下面是另一种方法：

# Separate out values (NOTE- this assumes you'll always have two strings in list)
df['pos_0'] = df['Feedback'].str[0]
df['pos_1'] = df['Feedback'].str[1]

df
        Name                     Feedback           pos_0      pos_1
0  Project A  [we should do x, went well]  we should do x  went well
1  Project B         [eat pop tarts, boo]   eat pop tarts        boo
2  Project C                   [bar, baz]             bar        baz

期望输出：

pd.melt(df, 'Name', ['pos_0', 'pos_1'], 'Feedback').drop('Feedback', axis=1)
        Name           value
0  Project A  we should do x
1  Project B   eat pop tarts
2  Project C             bar
3  Project A       went well
4  Project B             boo
5  Project C             baz

---

啊!！谢谢@Psidom…没有考虑列表的理解..我最初尝试使用堆栈/取消堆栈的方法出错了。您的反馈栏属于列表类型，有点不规则。所以堆栈/非堆栈方法在这里不会有多大帮助！谢谢@Psidom…没有考虑列表的理解..我最初尝试使用堆栈/取消堆栈的方法出错了。您的反馈栏属于列表类型，有点不规则。因此，堆栈/取消堆栈方法在这里没有多大帮助。这可能也是一本好读物：这也可能是一本好读物：