Graphene Python列出所有字段的解析空值
我正在python中使用GraphQL,我试图解析列表数据,但字段解析为null。如何让他们返回实际的列表数据 下面是我的代码片段Graphene Python列出所有字段的解析空值,python,graphql,graphene-python,Python,Graphql,Graphene Python,我正在python中使用GraphQL,我试图解析列表数据,但字段解析为null。如何让他们返回实际的列表数据 下面是我的代码片段 import graphene class User(graphene.ObjectType): """ Type definition for User """ id = graphene.Int() username = graphene.String() email = graphene.String() class Qu
import graphene
class User(graphene.ObjectType):
""" Type definition for User """
id = graphene.Int()
username = graphene.String()
email = graphene.String()
class Query(graphene.ObjectType):
users = graphene.List(User)
def resolve_users(self, args):
resp = [{'id': 39330, 'username': 'RCraig', 'email':
'WRussell@dolor.gov', 'teamId': 0}, {'id': 39331,
'username': 'AHohmann','email': 'AMarina@sapien.com',
'teamId': 0}]
return resp
schema = graphene.Schema(query=Query)
该代码段可以在以下位置进行测试:
这是我目前的问题
以及不期望的反应
您需要返回用户的对象,而不仅仅是字典:
import graphene
class User(graphene.ObjectType):
""" Type definition for User """
id = graphene.Int()
username = graphene.String()
email = graphene.String()
class Query(graphene.ObjectType):
users = graphene.List(User)
def resolve_users(self, args):
resp = [User(id=39330, username='RCraig', email='WRussell@dolor.gov')]
return resp
schema = graphene.Schema(query=Query)
您可以签入。此代码只返回一个列表(一组id、用户名、电子邮件)。如何返回多个集合?@jigarshah我知道这已经晚了,但您只需在上面的代码中添加更多的
User
对象到resp
。