转换MATLAB'时出错；s datenum到Python'；日期时间

我必须将MATLAB的datenum转换为Python的

datetime

。 以下代码如下：

import datetime
matlab_datenum = 63650571169.50261
python_datetime = datetime.date.fromordinal(int(matlab_datenum)) + \
    datetime.timedelta(days=matlab_datenum%1) - datetime.timedelta(days=366)
print(matlab_datenum)

上述代码生成此错误：

OverflowError: Python int too large to convert to C long

---

如何解决此问题？

您的datenum以秒为单位，与matlab历元相距。要转换为

datetime

，需要将秒数偏移为python理解的

datetime

。此函数使用Unix历元作为该引用

代码：

import datetime as dt

# define some constants
epoch = dt.datetime(1970, 1, 1)
matlab_to_epoch_days = 719529  # days from 1-1-0000 to 1-1-1970
matlab_to_epoch_seconds = matlab_to_epoch_days * 24 * 60 * 60

def matlab_to_datetime(matlab_date_num_seconds):
    # get number of seconds from epoch
    from_epoch = matlab_date_num_seconds - matlab_to_epoch_seconds

    # convert to python datetime
    return epoch + dt.timedelta(seconds=from_epoch)

print(matlab_to_datetime(63650571169.50261))

2017-01-01 10:12:49.502609

测试代码：

import datetime as dt

# define some constants
epoch = dt.datetime(1970, 1, 1)
matlab_to_epoch_days = 719529  # days from 1-1-0000 to 1-1-1970
matlab_to_epoch_seconds = matlab_to_epoch_days * 24 * 60 * 60

def matlab_to_datetime(matlab_date_num_seconds):
    # get number of seconds from epoch
    from_epoch = matlab_date_num_seconds - matlab_to_epoch_seconds

    # convert to python datetime
    return epoch + dt.timedelta(seconds=from_epoch)

print(matlab_to_datetime(63650571169.50261))

2017-01-01 10:12:49.502609

结果：

import datetime as dt

# define some constants
epoch = dt.datetime(1970, 1, 1)
matlab_to_epoch_days = 719529  # days from 1-1-0000 to 1-1-1970
matlab_to_epoch_seconds = matlab_to_epoch_days * 24 * 60 * 60

def matlab_to_datetime(matlab_date_num_seconds):
    # get number of seconds from epoch
    from_epoch = matlab_date_num_seconds - matlab_to_epoch_seconds

    # convert to python datetime
    return epoch + dt.timedelta(seconds=from_epoch)

print(matlab_to_datetime(63650571169.50261))

2017-01-01 10:12:49.502609

---

您的datenum以秒为单位。要转换为

datetime

，需要将秒数偏移为python理解的

datetime

。此函数使用Unix历元作为该引用

代码：

import datetime as dt

# define some constants
epoch = dt.datetime(1970, 1, 1)
matlab_to_epoch_days = 719529  # days from 1-1-0000 to 1-1-1970
matlab_to_epoch_seconds = matlab_to_epoch_days * 24 * 60 * 60

def matlab_to_datetime(matlab_date_num_seconds):
    # get number of seconds from epoch
    from_epoch = matlab_date_num_seconds - matlab_to_epoch_seconds

    # convert to python datetime
    return epoch + dt.timedelta(seconds=from_epoch)

print(matlab_to_datetime(63650571169.50261))

2017-01-01 10:12:49.502609

测试代码：

import datetime as dt

# define some constants
epoch = dt.datetime(1970, 1, 1)
matlab_to_epoch_days = 719529  # days from 1-1-0000 to 1-1-1970
matlab_to_epoch_seconds = matlab_to_epoch_days * 24 * 60 * 60

def matlab_to_datetime(matlab_date_num_seconds):
    # get number of seconds from epoch
    from_epoch = matlab_date_num_seconds - matlab_to_epoch_seconds

    # convert to python datetime
    return epoch + dt.timedelta(seconds=from_epoch)

print(matlab_to_datetime(63650571169.50261))

2017-01-01 10:12:49.502609

结果：

import datetime as dt

# define some constants
epoch = dt.datetime(1970, 1, 1)
matlab_to_epoch_days = 719529  # days from 1-1-0000 to 1-1-1970
matlab_to_epoch_seconds = matlab_to_epoch_days * 24 * 60 * 60

def matlab_to_datetime(matlab_date_num_seconds):
    # get number of seconds from epoch
    from_epoch = matlab_date_num_seconds - matlab_to_epoch_seconds

    # convert to python datetime
    return epoch + dt.timedelta(seconds=from_epoch)

print(matlab_to_datetime(63650571169.50261))

2017-01-01 10:12:49.502609

---

63650571169.50261

这个数字似乎很大，是一个MATLAB datenum首先，MATLAB datenum是从10000年1月0日开始的天数，这个数字相当于174385126年。这是外星人联系的时间吗？溢出问题可能与此63650571169有关。50261是一个datenum，表示日期加时间，例如2010-11-04 00:03:50.209589。那么，我怎样才能获得一个日期加一个时间呢？

63650571169.50261

这个数字对于MATLAB datenum来说似乎很大首先，MATLAB datenum是从10000年1月0日开始的天数，这个数字相当于174385126年。这是外星人联系的时间吗？溢出问题可能与此63650571169有关。50261是一个datenum，表示日期加时间，例如2010-11-04 00:03:50.209589。那么，我怎样才能获得一个日期加一个时间呢？