Python 如何在Pygame中生成额外的矩形?

Python 如何在Pygame中生成额外的矩形?,python,python-3.x,random,pygame,Python,Python 3.x,Random,Pygame,我正在制作一个简单的游戏,但我遇到了一个问题 游戏是这样的: “白色方块”吃“绿色方块” 问题: 如何生成“新的红色方块”并在每次“白色方块”吃掉“绿色方块”时都留在屏幕上 代码如下: import pygame, sys from random import randint from pygame.locals import* pygame.init() gameDisplay = pygame.display.set_mode((800, 600)) pygame.display.set

我正在制作一个简单的游戏,但我遇到了一个问题

游戏是这样的: “白色方块”吃“绿色方块”

问题:
如何生成“新的红色方块”并在每次“白色方块”吃掉“绿色方块”时都留在屏幕上

代码如下:

import pygame, sys
from random import randint
from pygame.locals import*


pygame.init()
gameDisplay = pygame.display.set_mode((800, 600))
pygame.display.set_caption("Square-it")
clock = pygame.time.Clock()

"Green Square"
green_x = randint(10, 780)
green_y = randint(10, 580)
green_width = 15
green_height = 15
green_color = pygame.Color("green")
green = pygame.Rect(green_x, green_y, green_width, green_height)

"Red Square"
red_x = randint(20, 780)
red_y = randint(20, 580)
red_width = 10
red_height = 10
red_color = pygame.Color("red")
red = pygame.Rect(red_x, red_y, red_width, red_height)

"White Square"
white_x = 400
white_y = 300
white_width = 10
white_height = 10
white_color = pygame.Color("white")
white = pygame.Rect(white_x, white_y, white_width, white_height)

while True:

    clock.tick(60)
    gameDisplay.fill((0, 20, 5))
    gameDisplay.fill(white_color, white)
    gameDisplay.fill(green_color, green)
    gameDisplay.fill(red_color, red)
    pygame.display.update()

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
           sys.exit()

    '''When White eats Green, Green regenerates'''
    if white.colliderect(green):
        green = pygame.Rect(randint(10, 780), randint(10, 580), green_width, green_height)

    '''White Square Movement'''
    keys = pygame.key.get_pressed()
    if keys[K_LEFT]:
        white.left = white.left - 10

    if keys[K_RIGHT]:
        white.right = white.right + 10

    if keys[K_UP]:
        white.top = white.top - 10

    if keys[K_DOWN]:
        white.bottom = white.bottom + 10

您应该首先创建一个数组来存储所有红色矩形实例

red_square_list = []
当白色矩形与绿色矩形碰撞时,应提取绿色矩形的x、y位置,并在此位置创建红色矩形的实例

为此,我建议使用类,但首先可以创建一个函数来创建一个红色矩形:

def create_red_square(x, y)
    red_width = 10
    red_height = 10
    red_color = pygame.Color("red")
    red = pygame.Rect(red_x, red_y, red_width, red_height)
    return red
现在,每次白色与绿色碰撞时,必须提取绿色矩形位置,并使用上面的函数显示红色矩形:

if white.colliderect(green):
    pos_x, pos_y = green.left, green.top
    green = pygame.Rect(randint(10, 780), randint(10, 580), green_width, green_height)
    red_square_list.append(create_red_square(pos_x, pos_y))
最后一行仅用于存储红色矩形,如果您以后想使用它们(就像您对绿色/白色矩形所做的那样)

我希望有帮助

编辑#1:

我犯的一些小错误是前面的代码,这是一个可行的解决方案:

` 导入pygame,sys 从随机导入randint 从pygame.locals导入*

red_square_list = []

pygame.init()
gameDisplay = pygame.display.set_mode((800, 600))
pygame.display.set_caption("Square-it")
clock = pygame.time.Clock()
red_color = pygame.Color("red")

"Green Square"
green_x = randint(10, 780)
green_y = randint(10, 580)
green_width = 15
green_height = 15
green_color = pygame.Color("green")
green = pygame.Rect(green_x, green_y, green_width, green_height)

def create_red_square(x, y):
    """Return one instance of Rect at position x, y"""
    red_width = 10
    red_height = 10
    red = pygame.Rect(x, y, red_width, red_height)
    return red

"White Square"
white_x = 400
white_y = 300
white_width = 10
white_height = 10
white_color = pygame.Color("white")
white = pygame.Rect(white_x, white_y, white_width, white_height)

while True:

    clock.tick(60)
    gameDisplay.fill((0, 20, 5))
    gameDisplay.fill(white_color, white)
    gameDisplay.fill(green_color, green)
    for each in red_square_list: #display all red rect
        gameDisplay.fill(red_color, each)
    pygame.display.update()

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
           sys.exit()

    '''When White eats Green, Green regenerates'''
    if white.colliderect(green):
        # extract green rect position
        pos_left, pos_top = green.left, green.top 
        # store the new red rectangle in the array
        red_square_list.append(create_red_square(pos_left+2, pos_top+2))
        # +2 is required as red square are 10x10 and green 15x15
        # new rect green
        new_left = randint(10, 780)
        new_top = randint(10, 580)
        green = pygame.Rect(new_left, new_top, green_width, green_height)


    '''White Square Movement'''
    keys = pygame.key.get_pressed()
    if keys[K_LEFT]:
    white.left = white.left - 10

    if keys[K_RIGHT]:
        white.right = white.right + 10

    if keys[K_UP]:
        white.top = white.top - 10

    if keys[K_DOWN]:
        white.bottom = white.bottom + 10

我希望这会有所帮助,

谢谢Nicolas M。感谢你的努力,不幸的是,我尝试了它,但它对我仍然不起作用:/有没有办法,当白色与绿色碰撞时,在屏幕上随机生成一个新的红色方块并保持其位置?对不起,我犯了两个错误(方块位置不正确,移动了2px),我忘了添加一个循环来显示它们并声明函数的颜色。现在它工作了!