Python 2.7错误：name'；葡萄酒'；没有定义

每当运行以下代码时，我都会收到错误消息“NameError:name'wine'未定义”：

def pub():
 print ("Welcome to the pub; what will you be drinking tonight?")
 answer = input("Choose the type of beverage you desire")
 if answer == " Beer" or answer == " beer":
    print ("You've come to the right place; have a seat!")
 elif answer == " Wine" or answer == " wine":
    print ("Sorry, we don't serve wine here. Why don't you try next door?")
 elif answer == " Cocktails" or answer == " cocktails" : 
    print ("Cocktails? who drinks those anymore?")
 elif answer == " Liquor" or answer == " liquor":
    print ("Sorry, we don't serve hard drinks here.")
 else:
    print ("You didn't pick a legitimate drink; try again!") 
pub()
def beer_selection():
   print ("Now we need to know what types of beers you're into. Select one of      the \
following flavor profiles:")
flavor_profiles = ["Rich and malty", "Crisp and hoppy", "Light and fruity",    "Smooth and balanced", "Piney and hoppy"]

任何帮助都将不胜感激

试试看：

raw_input()

而不是：

input()

---

问题是您的输入正在被评估。这是Python2.x中

input（）

的行为。由于没有名为

wine

的变量，因此会引发异常。您可以通过键入

“Wine”

（带双引号）来检查此行为，这很好，因为它现在是作为字符串而不是变量名输入的

您可以改用

raw_input（）

，它将与您的值

Wine

一起使用，即：

answer = raw_input("Choose the type of beverage you desire")

---

您可能正在使用python 2.7

对于Python2.7，“输入”是“原始输入”

将输入函数替换为

 answer = raw_input("Choose the type of beverage you desire:")

---

这真的是整个剧本吗；这就是问题所在。我在实验室里使用的是Python3.5，但忘了家里的电脑上安装了一个旧版本。谢谢大家的帮助！