不在列表中追加重复项-python

我的代码是：

for datum in data :
        sick.append(datum[2])

结果是

sick=['J02', 'J02', 'J20', 'J20', 'J20', 'J20', 'J20', 'A08', 'J45','A08']

我想要的是

if sick[i] == sick[i+1], don't appned value

sick=['J02', 'J20', 'A08', 'J45','A08'] <-- this isn't removing duplicates. I just don't want to append "if sick[i] == sick[i+1]"

所以我想要的结果是

if sick[i] == sick[i+1], don't appned value

sick=['J02', 'J20', 'A08', 'J45','A08'] <-- this isn't removing duplicates. I just don't want to append "if sick[i] == sick[i+1]"

sick=['J02'，'J20'，'A08'，'J45'，'A08']我的建议：

for datum in data :
    if not datum in sick:
        sick.append(datum)

我的建议是：

for datum in data :
    if not datum in sick:
        sick.append(datum)

您可以使用以下命令

data = ['J02', 'J02', 'J20', 'J20', 'J20', 'J20', 'J20', 'A08', 'J45']
sick=[]

for datum in data:
    if datum not in data:
       sick.append(datum)

这将提供以下输出：

['J02', 'J20', 'A08', 'J45']

您可以使用以下命令

data = ['J02', 'J02', 'J20', 'J20', 'J20', 'J20', 'J20', 'A08', 'J45']
sick=[]

for datum in data:
    if datum not in data:
       sick.append(datum)

这将提供以下输出：

['J02', 'J20', 'A08', 'J45']

如果允许重复，则这将起作用：

for datum in data:
    if len(sick) == 0 or sick[-1] != datum:
        sick.append(datum)

如果允许重复，则这将起作用：

for datum in data:
    if len(sick) == 0 or sick[-1] != datum:
        sick.append(datum)

从集合导入订单信息；sick=列表（OrderedDict.fromkeys（数据[2]用于数据中的数据））
来自集合导入OrderedDict；sick=列表（OrderedDict.fromkeys（数据[2]用于数据中的数据））