有没有一种方法可以创建一个用户列表，以便使用python将新用户添加到一个简单的游戏中？

我正在尝试创建一个简单的游戏（掷骰子），允许您添加多个用户，我遇到了一些问题。现在我的问题是我无法从嵌套循环中正确地获得列表输出。（我知道值需要打印，但我有点卡住了）

预期结果：要打印的列表“这是返回玩家列表”

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实际结果：陷入while循环

正如我在评论中提到的，似乎有两个问题。第一，在

login（）函数中有一个无限循环。而（真的）永远是真的。在下面的代码中，我将用于检索用户数量的用户输入的函数分离到它自己的函数中。此函数利用python没有显式类型的事实（这意味着您可以更改同一变量的类型）

第二个问题是，
login（）
函数不返回任何内容。这意味着在
game\u start（）
函数中，
users=login（）
行将始终为空。这将使您的下一行失败，因为您没有用户列表。我在下面添加了返回语句

尽可能接近原始发布的解决方案

def login():
    while True: 
        try:
            user_count = int(input("Enter the number of users that wish to play..."))
            print("The number of user is: ", user_count)

            username = []

            for i in range(1,user_count + 1):
             username.append(input(f"What is player {i} name?"))
             print(f'Welcome, {username[i-1]} you have been successfully logged in.')
            return username

        except ValueError:
            print("Oops! That was no vaild number. Try again...")


利用非显式键入解决问题的旧方法
=================================================

def getUserCount():
    user="NULL"
    while(type(user)!= int):
        userTemp=input("Enter the number of users that wish to play: ")
        try:
            user=int(userTemp)
        except ValueError:
            print("Oops! That was no vaild number. Try again...")
    return user

def login():
    user_count=getUserCount()
    print("The number of user is: ", user_count)
    username = []
    for i in range(1,user_count + 1):
        username.append(input(f"Enter player {i} name: "))
        print(f'Welcome, {username} you have been successfully logged in.')
    return username

下面是一个仅使用这两个函数的示例输出：

>>> login()
Enter the number of users that wish to play: nope
Oops! That was no vaild number. Try again...
Enter the number of users that wish to play: not
Oops! That was no vaild number. Try again...
Enter the number of users that wish to play: gonna
Oops! That was no vaild number. Try again...
Enter the number of users that wish to play: work
Oops! That was no vaild number. Try again...
Enter the number of users that wish to play: 3
The number of user is:  3
Enter player 1 name: one
Welcome, ['one'] you have been successfully logged in.
Enter player 2 name: two
Welcome, ['one', 'two'] you have been successfully logged in.
Enter player 3 name: three
Welcome, ['one', 'two', 'three'] you have been successfully logged in.
['one', 'two', 'three']

正如您所看到的，在login（）函数中打印username会打印整个数组，我敢肯定这是不需要的。我已经用下面的
login（）
定义解决了这个问题

def login():
    user_count=getUserCount()
    print("The number of user is: ", user_count)
    username = []
    for i in range(1,user_count + 1):
        username.append(input(f"Enter player {i} name: "))
        #username[i-1] since i starts at 1 and not 0
        print(f'Welcome, {username[i-1]} you have been successfully logged in.')
    return username

提供的示例输出：

>>> login()
Enter the number of users that wish to play: strings?
Oops! That was no vaild number. Try again...
Enter the number of users that wish to play: *@#
Oops! That was no vaild number. Try again...
Enter the number of users that wish to play: 3
The number of user is:  3
Enter player 1 name: one
Welcome, one you have been successfully logged in.
Enter player 2 name: four
Welcome, four you have been successfully logged in.
Enter player 3 name: seven
Welcome, seven you have been successfully logged in.
['one', 'four', 'seven']

你永远不会跳出while循环你似乎在任何时候都不会退出while循环，你只是将它设置为while True，并且永远不会告诉计算机跳出while循环这里有一些奇怪的事情。第一，while循环没有退出条件。While（true）将始终为true，因此它将不断要求您输入用户。我立即注意到的第二件事是，登录函数没有返回语句。这意味着用户的game_start（）方法变量将始终为空。这将阻止你的游戏（用户）方法工作，如果我使用返回打破我的while循环，它不会返回我需要的值。我以前也尝试过类似的方法，但不必破例，因为它是有效的。但是，当我使用列表时，它不是t@TokenThinker没问题。关于我分享的任何问题，请让我知道！我从周一到周五在一天中的不同时间进行检查。如果愿意的话，我可能能够在不使用python允许的类型更改的情况下提出一个解决方案，但这需要比我现在花费更多的时间。@Token实际上我刚刚意识到解决您的问题相当简单。您只需要一个return语句，而不需要为键入用户输入做很多额外的工作。现在添加最接近的原始更改
>>> login()
Enter the number of users that wish to play: strings?
Oops! That was no vaild number. Try again...
Enter the number of users that wish to play: *@#
Oops! That was no vaild number. Try again...
Enter the number of users that wish to play: 3
The number of user is:  3
Enter player 1 name: one
Welcome, one you have been successfully logged in.
Enter player 2 name: four
Welcome, four you have been successfully logged in.
Enter player 3 name: seven
Welcome, seven you have been successfully logged in.
['one', 'four', 'seven']