Python 重复字典列表将单个条目复制到另一个列表
又是新手问题Python 重复字典列表将单个条目复制到另一个列表,python,dictionary,list,Python,Dictionary,List,又是新手问题 假设我有一个嵌套字典列表 a = [{"value1": 1234, "value2": 23423423421, "value3": norway, "value4": charlie}, {"value1": 1398, "value2": 23423412221, "value3": england, "value4": alpha}, {"value1": 1234, "value2": 23234231221, "value3": norway, "v
假设我有一个嵌套字典列表
a = [{"value1": 1234, "value2": 23423423421, "value3": norway, "value4": charlie},
{"value1": 1398, "value2": 23423412221, "value3": england, "value4": alpha},
{"value1": 1234, "value2": 23234231221, "value3": norway, "value4": charlie},
{"value1": 1398, "value2": 23423213121, "value3": england, "value4": alpha}]
我想要的是移动每个副本的条目,其中value1、value3和value4匹配。结果应该如下所示:
b = [{"value1": 1398, "value2": 23423412221, "value3": england, "value4": alpha},
{"value1": 1234, "value2": 23234231221, "value3": norway, "value4": charlie}]
import itertools
import pprint
import operator
alpha, charlie, norway, england = range(4)
a = [{"value1": 1234, "value2": 23423423421, "value3": norway, "value4": charlie},
{"value1": 1398, "value2": 23423412221, "value3": england, "value4": alpha},
{"value1": 1234, "value2": 23234231221, "value3": norway, "value4": charlie},
{"value1": 1398, "value2": 23423213121, "value3": england, "value4": alpha}]
getvals = operator.itemgetter('value1', 'value3', 'value4')
a.sort(key=getvals)
b = [g.next() for _, g in itertools.groupby(a, getvals)]
pprint.pprint(b)
原始列表a应保持其原始状态。最近有一个类似的问题。试试这个 事实上,您提出了这个问题:“假设存在多个条目,其中value3和value4与其他嵌套字典相同。如何快速轻松地查找和删除这些重复的字典。” 听起来是一样的,对吧 编辑:大量窃取Alex的代码,看起来像这样:
b = [{"value1": 1398, "value2": 23423412221, "value3": england, "value4": alpha},
{"value1": 1234, "value2": 23234231221, "value3": norway, "value4": charlie}]
import itertools
import pprint
import operator
alpha, charlie, norway, england = range(4)
a = [{"value1": 1234, "value2": 23423423421, "value3": norway, "value4": charlie},
{"value1": 1398, "value2": 23423412221, "value3": england, "value4": alpha},
{"value1": 1234, "value2": 23234231221, "value3": norway, "value4": charlie},
{"value1": 1398, "value2": 23423213121, "value3": england, "value4": alpha}]
getvals = operator.itemgetter('value1', 'value3', 'value4')
a.sort(key=getvals)
b = [g.next() for _, g in itertools.groupby(a, getvals)]
pprint.pprint(b)
结果是:
[{'value1': 1234, 'value2': 23423423421L, 'value3': 2, 'value4': 1},
{'value1': 1398, 'value2': 23423412221L, 'value3': 3, 'value4': 0}]
如何定义两个重复的目录?他们所有的值都相等或者只是“值1”或者…?没关系,我解决了。我如何删除它:)你不需要。你发布你的答案是为了让其他人受益。当然,我会的。给我几秒钟。“假设我有一个嵌套字典列表。”您的示例是一个简单字典列表。没有嵌套的内容。请提供带有“嵌套”词典的示例,或删除“嵌套”一词。当单词与示例代码不匹配时,会令人困惑。