从python在终端执行命令时遇到问题

我有以下命令

/usr/bin/node_modules/phantomjs/bin/phantomjs RequestURL.jshttps://www.ubank.com.au/ >html

，它在终端可以很好地执行，但不能从python中执行，如下所示

def get_generated_html(self, url, has_headers):
        """
        Method: Method to get the generated HTML content from Phantomas.

        Args: Takes the url as an argument for which to get the HTML content.
              hasHeaders defaulted to false for no headers.

        Returns: Nothing.
        """
        if not urlparse(url).scheme:
            url = 'http://'+url
        if has_headers == False:
            command = PAGE_SOURCE_CMD % url
            utils.execute_command(command).communicate()
        else:
            command = FEO_PAGE_SOURCE_CMD % url
            print command
            utils.execute_command(command).communicate()

def start_parser(self, analysis_id, url, hasHeaders=False):
        """
        Method: Method to start the parser.

        Args: Analsyis ID and URL as an argument.

        Returns: Nothing.
        """

        feed = None
        path = self.create_analysis_folder(analysis_id, hasHeaders) 
        self.get_generated_html(url, hasHeaders)
        for root, dirs, files in os.walk(path):
            for file in files:
                if file.endswith('.html'):
                    feed = BeautifulSoup(open(path + '/' +file).read())
                    if hasHeaders:
                        os.chdir('..')
                    print "deleting"
                    shutil.rmtree(os.getcwd())
            break
        return feed

print语句打印出确切的命令

下面是execute_command（）方法

我调用生成的html，如下所示

def get_generated_html(self, url, has_headers):
        """
        Method: Method to get the generated HTML content from Phantomas.

        Args: Takes the url as an argument for which to get the HTML content.
              hasHeaders defaulted to false for no headers.

        Returns: Nothing.
        """
        if not urlparse(url).scheme:
            url = 'http://'+url
        if has_headers == False:
            command = PAGE_SOURCE_CMD % url
            utils.execute_command(command).communicate()
        else:
            command = FEO_PAGE_SOURCE_CMD % url
            print command
            utils.execute_command(command).communicate()

def start_parser(self, analysis_id, url, hasHeaders=False):
        """
        Method: Method to start the parser.

        Args: Analsyis ID and URL as an argument.

        Returns: Nothing.
        """

        feed = None
        path = self.create_analysis_folder(analysis_id, hasHeaders) 
        self.get_generated_html(url, hasHeaders)
        for root, dirs, files in os.walk(path):
            for file in files:
                if file.endswith('.html'):
                    feed = BeautifulSoup(open(path + '/' +file).read())
                    if hasHeaders:
                        os.chdir('..')
                    print "deleting"
                    shutil.rmtree(os.getcwd())
            break
        return feed

---

此处返回的提要不是页面源，因为它是从命令行返回的。

我不确定

get\u generated\u html

应该做什么，但它不返回任何内容，在其中一种情况下，它只

print

。我被docstring搞糊涂了，因为它说函数不应该返回任何内容，但它也没有说任何关于输出的内容。“默认值为false”部分在当前代码中不正确

另外，返回一个元组，因此您将只返回返回值的一个元素（可能）

尝试以下方法：

output = utils.execute_command(command).communicate()
return output[0]

如果我们正在进行代码审查，这对我来说更优雅：

if not has_headers:
    command = PAGE_SOURCE_CMD % url
else:
    command = FEO_PAGE_SOURCE_CMD % url
output = utils.execute_command(command).communicate()
return output[0]  # or print it?

---

也许

PAGE\u SOURCE\u CMD

有问题，或者调用

get\u generated\u html

？“我看不出有什么明显的错误，所以也许有更多的背景？”在问题中补充道，“关心”对否决票发表评论？我想我回答了这个问题（“有帮助吗？”）。从coamnd行执行命令将打印html源代码。从脚本内部它不会打印任何内容，所以我关于不打印或返回任何内容的评论可能有用吗？