Python 将具有逗号分隔值的记录转换为集合

我有一个包含多个记录的字符串。每个记录都有一个由逗号分隔的不同单词列表。我想将每个记录转换成一个集合，其中记录中的单词就是集合中的值。你能告诉我如何把它转换成一套吗

{'citrus fruit','semi-finished bread','margarine','ready soups'}
{'tropical fruit','yogurt','coffee'}

下面是一个文件中的两条记录

citrus fruit,semi-finished bread,margarine,ready soups
tropical fruit,yogurt,coffee

{'citrus fruit','semi-finished bread','margarine','ready soups'}
{'tropical fruit','yogurt','coffee'}

我想将其转换为：

{'citrus fruit','semi-finished bread','margarine','ready soups'}
{'tropical fruit','yogurt','coffee'}

使用csv模块

{'citrus fruit','semi-finished bread','margarine','ready soups'}
{'tropical fruit','yogurt','coffee'}

import csv

def readsets(filename):
    with open(filename) as f:
        for row in csv.reader(f):
            yield set(row)

---

我不相信你想要一个

集合

，因为在你的例子中，你是按你想要的结果顺序列出所有东西的<代码>集合s是无序的，不能包含重复项。也不清楚您的记录是如何分隔的

{'citrus fruit','semi-finished bread','margarine','ready soups'}
{'tropical fruit','yogurt','coffee'}

下面是一个使用

list

维护订单的示例：

{'citrus fruit','semi-finished bread','margarine','ready soups'}
{'tropical fruit','yogurt','coffee'}

>>> first_record = "citrus fruit,semi-finished bread,margarine,ready soups"
>>> second_record = "tropical fruit,yogurt,coffee"
>>> def tokenize(s, delim=","):
...   return s.split(delim)
... 
>>> first_result = tokenize(first_record)
>>> first_result
['citrus fruit', 'semi-finished bread', 'margarine', 'ready soups']
>>> second_result = tokenize(second_record)
>>> second_result
['tropical fruit', 'yogurt', 'coffee']

如果您真的想要一个

集合

，只需将其包装在对

集合

构造函数的调用中：

{'citrus fruit','semi-finished bread','margarine','ready soups'}
{'tropical fruit','yogurt','coffee'}

>>> first_result_set = set(first_result)
>>> second_result_set = set(second_result)
>>> first_result_set
{'margarine', 'ready soups', 'semi-finished bread', 'citrus fruit'}
>>> second_result_set
{'coffee', 'yogurt', 'tropical fruit'}

编辑：您可以在一个shebang中完成所有操作，因为我们知道记录由换行符分隔：

{'citrus fruit','semi-finished bread','margarine','ready soups'}
{'tropical fruit','yogurt','coffee'}

>>> records = "citrus fruit,semi-finished bread,margarine,ready soups\ntropical fruit,yogurt,coffee"
>>> def setitize_records(records, record_delim="\n", item_delim=","):
...   record_list = records.split(record_delim)
...   record_sets = [set(record.split(",")) for record in record_list]
...   return record_sets
... 
>>> result = setitize_records(records)
>>> result
[{'margarine', 'ready soups', 'semi-finished bread', 'citrus fruit'}, {'coffee', 'yogurt', 'tropical fruit'}]

---

这应该对你有用。看看吧

{'citrus fruit','semi-finished bread','margarine','ready soups'}
{'tropical fruit','yogurt','coffee'}

rec = "citrus fruit,semi-finished bread,margarine,ready soups tropical
fruit,yogurt,coffee"
#result 
myset = set() 

while rec != "":
    head, _ , rec = rec.partition(',')
    myset.add(head)
print(myset)

---

你真的想要一个

集合

还是

列表

？

set

是一个无序的集合，没有重复项。

列表

是有序的，可能包含重复项。记录如何分隔？记录由新行字符分隔。需要一个set@aseempuri令人惊叹的！如果你觉得这个片段很有用，你也介意投票吗？