使用Python从CSV文件生成所有路径

我想用python制作一个程序，从csv文件生成所有可能的路径。我该怎么办

import pandas as pd
import csv

def dataInCol(fieldName):
    df = pd.read_csv('..\\data.csv',usecols=[fieldName])
    qr = df.values.tolist()
    flattened = [val for sublist in qr for val in sublist]
    return flattened


def makingPaths(dataCol, path = "Companies: "):
    with open('..\\data.csv', "rb") as f:
        reader = csv.DictReader(f)
        headers = reader.fieldnames
    for eachValue in dataCol:
        path = path + str(eachValue)
        if str(eachValue) in headers:
            newCol = dataInCol(str(eachValue))
            makingPaths(newCol)
        break
    return path

例如，在下图中：

公司->苹果->iPhone->iPhone4.0

公司->三星->Gtablet->SamTab7.0

公司->索尼->Xperia->Xperia4K

。。。 链接到数据：

---

这似乎是一个家庭作业问题，但我发现它很有趣，所以我做了以下几点：

csvfile = open('data.csv', 'r') #open the csv file
lines = csvfile.readlines() # read the file into a list, one line per element
headings = [cell.strip() for cell in lines[0].split(",")] #keep a clean list of headings
splitlines = []
for line in lines[1:]: # split each row into cells
    splitlines.append(line.split(",")) 
columns = zip(*splitlines); # convert rows to columns

def recursePrint(colval, text): # a recursive function to traverse the columns
        colval = colval.strip()
        if (colval in headings):
            for c in columns[headings.index(colval)]:
                newtext = text + colval + "->"
                recursePrint(c, newtext)
        else:
            print (text + colval)


for x in columns[0]:
    recursePrint(x, "") # run the recursion

以及输出：

Apple->iPhone->iPhone4.0
Apple->iPhone->iPhone4.7
Apple->iPhone->iPhone5.5
Apple->Macbook
Apple->iPad->iPadMini
Apple->iPad->iPadReg
Apple->iPad->iPadPro
Samsung->Galaxy->GalaxyS3
Samsung->Galaxy->GalaxyS4
Samsung->Galaxy->GalaxyS8
Samsung->Notebook->NSeries5
Samsung->Notebook->NSeries7
Samsung->Notebook->NSeries9
Samsung->Gtablet->SamTab7.0
Samsung->Gtablet->SamTab9.0
Samsung->Gtablet->
Sony->Xperia->Xperia4K
Sony->Xperia->XperiaUltra
Sony->Xperia->XperiaPrem
Sony->Xtablet->XTab6.0
Sony->Xtablet->XTab8.0
Sony->Xtablet->XTab10.0
Sony->

---

这似乎是一个家庭作业问题，但我发现它很有趣，所以我做了以下几点：

csvfile = open('data.csv', 'r') #open the csv file
lines = csvfile.readlines() # read the file into a list, one line per element
headings = [cell.strip() for cell in lines[0].split(",")] #keep a clean list of headings
splitlines = []
for line in lines[1:]: # split each row into cells
    splitlines.append(line.split(",")) 
columns = zip(*splitlines); # convert rows to columns

def recursePrint(colval, text): # a recursive function to traverse the columns
        colval = colval.strip()
        if (colval in headings):
            for c in columns[headings.index(colval)]:
                newtext = text + colval + "->"
                recursePrint(c, newtext)
        else:
            print (text + colval)


for x in columns[0]:
    recursePrint(x, "") # run the recursion

以及输出：

Apple->iPhone->iPhone4.0
Apple->iPhone->iPhone4.7
Apple->iPhone->iPhone5.5
Apple->Macbook
Apple->iPad->iPadMini
Apple->iPad->iPadReg
Apple->iPad->iPadPro
Samsung->Galaxy->GalaxyS3
Samsung->Galaxy->GalaxyS4
Samsung->Galaxy->GalaxyS8
Samsung->Notebook->NSeries5
Samsung->Notebook->NSeries7
Samsung->Notebook->NSeries9
Samsung->Gtablet->SamTab7.0
Samsung->Gtablet->SamTab9.0
Samsung->Gtablet->
Sony->Xperia->Xperia4K
Sony->Xperia->XperiaUltra
Sony->Xperia->XperiaPrem
Sony->Xtablet->XTab6.0
Sony->Xtablet->XTab8.0
Sony->Xtablet->XTab10.0
Sony->

---

将csv发布为文本将是一项改进…请将您的数据添加为文本，详细说明您正在尝试执行的操作，并添加到目前为止的代码。您所说的“路径”是什么意思？一个

str

对象还是什么？@AzatIbrakov是一个strobject@Jean-Françoisfare I发布了一个数据链接，将csv发布为文本将是一个改进…请将您的数据添加为文本，详细解释您正在尝试做什么，并添加到目前为止的代码。您所说的“路径”是什么意思？一个

str

对象还是什么？@AzatIbrakov是一个strobject@Jean-弗朗索瓦·法布雷一世发布了数据链接