如何在Python3中获取多行行的用户输入?
我知道常规输入函数可以接受单行,但只要您尝试编写一个字符串段落并按enter键输入下一行,它就会终止。有没有一种初学者友好的方法可以接受多行用户字符串输入作为变量?在程序中,一种常见的方法是使用一个“I'm done”(我完成了)字符串(例如,一个句点),并保持逐行读取,直到读取的行与该字符串匹配如何在Python3中获取多行行的用户输入?,python,input,multiline,Python,Input,Multiline,我知道常规输入函数可以接受单行,但只要您尝试编写一个字符串段落并按enter键输入下一行,它就会终止。有没有一种初学者友好的方法可以接受多行用户字符串输入作为变量?在程序中,一种常见的方法是使用一个“I'm done”(我完成了)字符串(例如,一个句点),并保持逐行读取,直到读取的行与该字符串匹配 print("Enter as many lines of text as you want.") print("When you're done, enter a single period on
print("Enter as many lines of text as you want.")
print("When you're done, enter a single period on a line by itself.")
buffer = []
while True:
print("> ", end="")
line = input()
if line == ".":
break
buffer.append(line)
multiline_string = "\n".join(buffer)
print("You entered...")
print()
print(multiline_string)
您可以使用sys库来实现这一点
import sys
x = sys.stdin.read()
虽然这可以解决这个问题,但您也希望提供一种摆脱循环的方法。否则,这将是无休止的多行用户输入。
Line=""
while True:
x=input()
Line=Line+" "+x
if "." in x:
break
print(Line)
def processString(x):
print(x.replace('process','whatever'))
lines = ""
while True:
if lines == "":
lines = ""
print("Enter string:")
x = input()
if x == "" and lines != "":
processString(lines)
break
else:
lines += x
# then hit enter once after multi-line string to process it
import sys
s = sys.stdin.read()
# print(s) # It will print everything
for line in s.splitlines(): # to read line by line
print(line)