Python can'；t访问my django应用程序数据库中的对象请帮助；-；

以下代码是我开始使用的django应用程序的代码。但是，我无法访问我独立创建的任何对象，我知道它们在数据库中以以下形式存在：

return HttpResponse(Details.objects.all())

提供所有数据的输出，但我无法使用代码访问对象：

return HttpResponse(ID1.email)

请帮忙

from django.shortcuts import render
from CollectMail.models import Details
from django.http import HttpResponse
import pandas as p
import os


file = p.read_csv(r"C:\Users\Robert Chomba Mumba\Desktop\Project At Access Bank 2\Emails\test_data_final.csv")

n = len(file['EMAIL'])
j = 0
k = 1
while j != n:
    NewItem = file['EMAIL'][j]
    NewObject = 'ID' + str(k)
    NewObject = Details(email = NewItem)
    NewObject.save()
    j +=1
    k +=1
#Object names are ID1,ID2,ID3....

def index(request):
    #return HttpResponse(Details.objects.all())
    return HttpResponse(ID2.email)

NewObject='ID'+str（k）只是创建一个字符串对象，然后用new Details（）实例覆盖它。至关重要的是，从来没有创建过对象

ID2

。我认为，你正在努力实现的目标可以这样做：

from django.shortcuts import render
from CollectMail.models import Details
from django.http import HttpResponse
import pandas as p
import os


def build_objects():
    res = dict()
    file = p.read_csv(r"C:\Users\Robert Chomba Mumba\Desktop\Project At Access Bank 2\Emails\test_data_final.csv")

    n = len(file['EMAIL'])
    j = 0
    k = 1
    while j != n:
        NewItem = file['EMAIL'][j]
        NewObject = Details(email = NewItem)
        NewObject.save()
        res['ID' + str(k)] = NewObject
        j +=1
        k +=1
    return res


def index(request):
    res = build_objects()
    return HttpResponse(res['ID2'].email)