Python concurrent.futures.ThreadPoolExecutor比列表理解速度慢

Python concurrent.futures.ThreadPoolExecutor比列表理解速度慢,python,concurrency,Python,Concurrency,我正在使用列表理解vs.concurrent.futures测试一个简单的函数: class Test: @staticmethod def something(times = 1): return sum([1 for i in range(times)]) @staticmethod def simulate1(function, N): l = [] for i in range(N):

我正在使用列表理解vs.concurrent.futures测试一个简单的函数:

class Test:

    @staticmethod
    def something(times = 1):
        return sum([1 for i in range(times)])

    @staticmethod
    def simulate1(function, N):
        l = []

        for i in range(N):
            outcome = function()
            l.append(outcome)

        return sum(l) / N

    @staticmethod
    def simulate2(function, N):
        import concurrent.futures

        with concurrent.futures.ThreadPoolExecutor(max_workers=10) as executor:
            l = [outcome for outcome in executor.map(lambda x: function(), range(N))]

        return sum(l) / N

    @staticmethod
    def simulate3(function, N):
        import concurrent.futures

        l = 0

        with concurrent.futures.ThreadPoolExecutor(max_workers=10) as executor:
            futures = [executor.submit(function) for i in range(N)]
            for future in concurrent.futures.as_completed(futures):
                l += future.result()

        return l / N

def simulation():
    simulationRate = 100000

    import datetime

    s = datetime.datetime.now()
    o = Test.simulate1(lambda : Test.something(10), simulationRate)
    print((datetime.datetime.now() - s))

    s = datetime.datetime.now()
    o = Test.simulate2(lambda : Test.something(10), simulationRate)
    print((datetime.datetime.now() - s))

    s = datetime.datetime.now()
    o = Test.simulate3(lambda : Test.something(10), simulationRate)
    print((datetime.datetime.now() - s))

simulation()
测量时间,我得到:

0:00:00.258000
0:00:10.348000
0:00:10.556000

我刚开始学习并发性,所以我不知道什么是阻碍线程更快运行的瓶颈。

如果将任务函数更改为此,您将看到不同之处:

def something(n):
    """ simulate doing some io based task.
    """
    time.sleep(0.001)
    return sum(1 for i in range(n))
在我的mac pro上,它提供:

0:00:13.774700
0:00:01.591226
0:00:01.489159
这一次,并发的未来显然更快了

原因是:您正在模拟一个基于cpu的任务,因为python的GIL,concurrent.future会使它变慢


concurrent.future为异步执行可调用项提供了一个高级接口,您在错误的场景中使用了它。

如果将任务函数更改为此,您将看到区别:

def something(n):
    """ simulate doing some io based task.
    """
    time.sleep(0.001)
    return sum(1 for i in range(n))
在我的mac pro上,它提供:

0:00:13.774700
0:00:01.591226
0:00:01.489159
这一次,并发的未来显然更快了

原因是:您正在模拟一个基于cpu的任务,因为python的GIL,concurrent.future会使它变慢

concurrent.future为异步执行可调用项提供了一个高级接口,但您在错误的场景中使用了它