在python中使用链表模拟排队 我几乎完全用C++来处理链表和类,所以我很难让它工作。第一个类应该有变量名,接下来是一个init函数、两个getter函数和两个setter函数。第二个类(行)应该有一个init函数和一个add函数,用于将项目添加到链表的末尾。我似乎无法使我的add函数工作。感谢您的帮助
这是我目前掌握的代码在python中使用链表模拟排队 我几乎完全用C++来处理链表和类,所以我很难让它工作。第一个类应该有变量名,接下来是一个init函数、两个getter函数和两个setter函数。第二个类(行)应该有一个init函数和一个add函数,用于将项目添加到链表的末尾。我似乎无法使我的add函数工作。感谢您的帮助,python,linked-list,Python,Linked List,这是我目前掌握的代码 class PersonList(): """ The class to represent the node in a linked list of people. It takes the variables: name, which represents the person's name, and next_person, which links the next person in the linked list. ""
class PersonList():
"""
The class to represent the node in a linked list of people. It takes the variables:
name, which represents the person's name, and next_person, which links the next
person in the linked list.
"""
def __init__(self, name = None, next_ = None):
self.__name = name
self.__next = next_
def getName(self):
return self.__name
def getNext(self):
return self.__next
def setName(self, new_name):
self.__name = new_name
def setNext(self, new_person):
self.__next = new_person
def __str__(self):
return (self.__name)
def printlist(node):
next_node = node.getNext()
while next_node != None:
next_node = node.getNext()
print (node)
node = node.getNext()
class Line():
""" The class that represents the line of people as the linked list. Takes the variable
head, that denotes the first person in the line
"""
def __init__(self, head = None):
self.head = None
def add(self, name):
if self.head == None:
self.head = PersonList(name)
else:
是一个选项还是只跟踪尾部,以避免每次添加内容时遍历整个列表:
class Line():
""" The class that represents the line of people as the linked list. Takes the variable
head, that denotes the first person in the line
"""
def __init__(self, head = None):
self.head = None
self.tail = None
def add(self, name):
tmp = PersonList(name)
if self.head == None:
self.head = tmp
self.tail = tmp
else:
self.tail.next = tmp
self.tail = tmp
“似乎无法让它工作”到底是什么意思?你似乎还没有完成它的实现……你能描述一下你在尝试添加一个人时看到的行为吗?在python中,您可能不需要像在c中那样实现它。您可以在
Line()
中对list
对象进行子类化,从而继承其append()
和其他list方法。我花了大约3-4个小时来尝试add函数的不同变体,并在一个主函数中测试它们。我所有的尝试都以一个没有连接到任何东西的名称结束。我怀疑列表遍历是赋值+1的一部分,因为这是一个更好的解决方案
class Line():
""" The class that represents the line of people as the linked list. Takes the variable
head, that denotes the first person in the line
"""
def __init__(self, head = None):
self.head = None
self.tail = None
def add(self, name):
tmp = PersonList(name)
if self.head == None:
self.head = tmp
self.tail = tmp
else:
self.tail.next = tmp
self.tail = tmp