python for循环if语句问题

当我们运行下面的foor循环时，它会多次输出同一对（见下文），尽管keptPairs只包含不同的元组。有人能快速解决这个问题吗

processedPairs = []
bestCorrPairs = []
corrCoefs = []
for pair in keptPairs:
    if pair not in processedPairs:
        processedPairs.append(pair)
        bestCorrCoef = 0
        targetx = pair[0]
        t_y = []
        for p in keptPairs:
            if targetx in p:
                if (p[0]!=targetx): t_y.append(p[0])
                else: t_y.append(p[1])
            else: continue
        for targety in t_y:
            corr = calcCorr(final_t,targetx, targety)
            if (np.abs(corr) > np.abs(bestCorrCoef) and not (corr==0 or corr==1)):
                bestCorrCoef = corr
                bestPair = tuple([targetx, targety])
            else: continue

        bestCorrPairs.append(bestPair)
        corrCoefs.append(bestCorrCoef)
    else: continue

for i in range(0,len(bestCorrPairs)):
    print(bestCorrPairs[i], ': ', corrCoefs[i])

输出：

我们只希望处理每一对。在第一个for循环之后打印对实际上只打印一次，但是，输出结果似乎这些对已经处理了多次。

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谢谢大家!

我认为是因为你没有重置你附加的两个变量（bestPair，bestCorrCoef）。。。当您启动for循环时，尝试重置这两个变量，或者您可以这样做：

for targety in t_y:
        corr = calcCorr(final_t,targetx, targety)
        if (np.abs(corr) > np.abs(bestCorrCoef) and not (corr==0 or corr==1)):
            bestCorrCoef = corr
            bestPair = tuple([targetx, targety])

            bestCorrPairs.append(bestPair)
            corrCoefs.append(bestCorrCoef)
        else: continue

for targety in t_y:
        corr = calcCorr(final_t,targetx, targety)
        if (np.abs(corr) > np.abs(bestCorrCoef) and not (corr==0 or corr==1)):
            bestCorrCoef = corr
            bestPair = tuple([targetx, targety])

            bestCorrPairs.append(bestPair)
            corrCoefs.append(bestCorrCoef)
        else: continue