Python 将循环附加到不同的列表上

假设我有这些值的列表：

['1', '91', '70', '2', '84', '69', '3', '86', '68', '4', '84', '68', '5', '83', '70', '6', '80', '68', '7', '86', '73', '8', '89', '71', '9', '84', '67', '10', '83', '65', '11', '80', '66', '12', '86', '63', '13', '90', '69', '14', '91', '72', '15', '91', '72', '16', '88', '72', '17', '97', '76', '18', '89', '70', '19', '74', '66', '20', '71', '64', '21', '74', '61', '22', '84', '61', '23', '86', '66', '24', '91', '68', '25', '83', '65', '26', '84', '66', '27', '79', '64', '28', '72', '63', '29', '73', '64', '30', '81', '63', '31', '73', '63']

如何将第一个元素置于三个元素之上，并将其附加到另一个列表中？例如，1，然后2，然后3。。。制造[1,2,3…31]

第二个分别是[91,84,86，…73]

第三个也一样[70，69，68……63]

有什么帮助吗

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我现在正在使用循环，并尝试将值附加到不同的列表中。

使用步长值对列表进行切片：

values = ['1', '91', '70', '2', '84', '69', '3', '86', '68', '4', '84', '68', 
          '5', '83', '70', '6', '80', '68', '7', '86', '73', '8', '89', '71', 
          '9', '84', '67', '10', '83', '65', '11', '80', '66', '12', '86',
          '63', '13', '90', '69', '14', '91', '72', '15', '91', '72', '16',
          '88', '72', '17', '97', '76', '18', '89', '70', '19', '74', '66',
          '20', '71', '64', '21', '74', '61', '22', '84', '61', '23', '86',
          '66', '24', '91', '68', '25', '83', '65', '26', '84', '66', '27',
          '79', '64', '28', '72', '63', '29', '73', '64', '30', '81', '63',
          '31', '73', '63']

values0 = values[0::3]
values1 = values[1::3]
values2 = values[2::3]

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您可以使用分步切片：

every_third = values[0::3]
every_third_plus_one = values[1::3]
every_third_plus_two = values[2::3]

…或更一般地在单个呼叫中：

def separate_list(a, stepsize):
    '''Separate list a into a number of lists by stepping through 
    at the given stepsize.'''
    return [a[s::stepsize] for s in xrange(stepsize)]
print separate_list(values, 3)

另一种选择：

a, b, c = zip(*zip(*[iter(values)]*3))

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或：步骤=3；valuessplit=[values[start:：step]对于rangestep中的start]我不一定将第二个示例称为单个迭代。切片是一个内循环，xrange是一个外循环。@StevenRumbalski很公平。下次当你有你尝试过的代码时，把它和你的问题一起发布。如果你这样做，你可能会得到更好的答案。