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Python re.sub()不替换表达式中的值_Python_Regex_Python 2.7 - Fatal编程技术网

Python re.sub()不替换表达式中的值

Python re.sub()不替换表达式中的值,python,regex,python-2.7,Python,Regex,Python 2.7,我想用z3Sigs替换v_uua,但下面的代码不能做到这一点 import re SigOnDecision = ['v__a', '__Vdly__v__a'] x = "(1 & v__a) == 0" for signs in SigOnDecision: p = "{}".format(signs) y = re.sub(p, "z3Sigs", x) print y 此代码仅打印x的原始值,即(1&v\u a)==0 有谁能指出错误是因为您没有修改y。仅替换x

我想用
z3Sigs
替换
v_uua
,但下面的代码不能做到这一点

import re
SigOnDecision = ['v__a', '__Vdly__v__a']
x = "(1 & v__a) == 0"
for signs in SigOnDecision:
    p = "{}".format(signs)
    y = re.sub(p, "z3Sigs", x)
print y
此代码仅打印
x
的原始值,即
(1&v\u a)==0

有谁能指出错误

是因为您没有修改
y
。仅替换
x的值

y = re.sub(p, "z3Sigs", x)
改为修改
x

x = re.sub(p, "z3Sigs", x)
或者将
y
设置为
x
并修改
y

y = x

for signs in SigOnDecision:
    y = re.sub(p, "z3Sigs", y)